conversion factors is the answer!
The correct answer would be A.The acceleration of gravity is <span>9.81 m/s^2. This is calculated by using the equation:
a = GM/r</span>²
where G is the gravitational constant 6.6726 x 10-11N-m2/kg2, M is the mass of the planet (<span>5.9736E+24 kg) and r is the radius of the planet.
</span>
Answer:
K= 95.4 J
Explanation:
For this exercise we must use the conservation of mechanical energy.
We set a reference system on the floor.
Starting point. Higher
Em₀ = U = m g h
Final point. Just before taking the floor
Em_f = K = ½ m v²
energy is conserved because there is no friction
Em₀ = Em_f
mg h = K
The height is
- h = y -y₀
h = 0- y₀
let's calculate
K = 3.23 (-9.81) (-3.01)
K= 95.4 J
The mechanical energy at top =Mechanical energy at bottom
- Mass=m=54kg
- Height=h=51m
- Acceleration due to gravity=g=10m/s^2
- Velocity=v=2.6m/s
- Final energy at bottom=The kinetic energy
Answer:
g=9.64m/s^2.
Explanation:
Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GMwhere G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3 is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).
