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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Physics

2 answers:

Sergeu [11.5K]3 years ago

6 0

Answer:

Sound energy to electric energy - a person talking into a microphone

Radiant energy to electric energy - sunlight falling on solar panels

Gravitational potential energy to motion energy - a ball dropped from a height

Explanation:

A person talking is the sound energy and going into an electric phone

Sunlight or Radiant energy falls onto the solar panels creating electric energy

The ball is being pulled down by gravity from a certain height, going down to the ground, it’s motion, falling

REY [17]3 years ago

3 0

a ball dropped from a height ==> gravitational potential energy to motion energy

sunlight falling on solar panels ==> radiant energy to electric energy

a person talking into a microphone ==> sound energy to electric energy

______________________________________

sound energy to electric energy ==> a person talking into a microphone

radiant energy to electric energy ==> sunlight falling on solar panels

gravitational potential energy to motion energy ==> a ball dropped from a height

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A person in a kayak starts paddling, and it accelerates from 0 to 0.61 m/s in a distance of 0.39 m. If the combined mass of the

Iteru [2.4K]

Answer:

35.3 N

Explanation:

U = 0, V = 0.61 m/s, s = 0.39 m

Let a be the acceleration.

Use third equation of motion

V^2 = u^2 + 2 as

0.61 × 0.61 = 0 + 2 × a × 0.39

a = 0.477 m/s^2

Force = mass × acceleration

F = 74 × 0.477 = 35.3 N

6 0

3 years ago

Unscramble the bolded letters to guess the 6 letter word code. Did you get the poses or exercises correct? MOUNTAIN POSE TRIANGL

nikitadnepr [17]

Explanation:

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3 years ago

To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0129-kg bullet i

ipn [44]

Answer:

t=0.42s

Explanation:

Here you have an inelastic collision. By the conservation of the momentum you have:

$m_1v_1+m_2v_2=(m_1+m_2)v$

m1: mass of the bullet

m2: wooden block mass

v1: velocity of the bullet

v2: velocity of the wooden block

v: velocity of bullet and wooden block after the collision.

By noticing that after the collision, both objects reach the same height from where the wooden block was dropped, you can assume that v is equal to the negative of v2. In other words:

$m_1(-v_1)+m_2v_2=(m1+m2)(-v2)$

Where you assumed that the negative direction is upward. By replacing and doing v2 the subject of the formula you get:

$-(0.0129kg)(767m/s)+(1.17kg)v_2=(1.1829kg)(-v_2)\\\\v_2=4.20m/s$

Now, with this information you can use the equation for the final speed of an accelerated motion and doing t the subject of the formula. IN other words:

$v_2=v_o+gt\\\\t=\frac{v_2-v_o}{g}=\frac{4.2m/s-0m/s}{9.8m/s^2}=0.42s$