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2 years ago

A house is advertised as having 1460 square feet under roof. What is the area of this house in square meters?

Physics

2 answers:

Vladimir [108]2 years ago

8 0

1400 is the story of the president Barack Obama

Wewaii [24]2 years ago

6 0

Answer: 131.92 m

Explanation: The problem give above is a conversion problem. To convert any measurement from one unit to another, we need a relation for the original units to that of the desired unit. This relation is called the conversion factor. It is used by multiplying or dividing the factor depending on what is the unit of the original measurement. For this case, we need to convert from ft^2 to m^2. The conversion factor would be 1 foot is equal to 0.3048 m. So, we would be getting the square of the factor and then multiply to the original value.

1420 ft^2 ( 0.3048 m / 1 ft)^2 = 131.92 m

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Technician A says that the governor is used to measure vehicle speed in a hydraulically-controlled automatic transmission. Techn

igor_vitrenko [27]

Answer:

Both technicians are correct

Explanation:

In automobiles, governors are being used. Governors are also known for speed limiters as they can regulate and measure the speed of the automobile.

Hydraulic Transmission: Shifting is controlled by mechanical sensors according to vehicle speed and throttle position/manifold vacuum through valving operated by hydraulic 'pilot' signals.

Electronic Transmission: Shifting is controlled by an on-board computer that receives signals from electronic sensors.

3 0

2 years ago

A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long

Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

$W=-\mu mg\times l$

Put the value into the formula

$W=-0.30\times62\times9.8\times3.50$

$W=-637.98\ J$

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

$K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}$

$\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}$

Final potential energy is zero

So, $\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2$

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl$

Put the value into the formula

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50$

$v_{2}=\sqrt{2\times55.915}$

$v_{2}=10.57\ m/s$

The speed of skier is 10.57 m/s.

Hence, (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0

2 years ago

Three examples that prove newton's law of motion

s344n2d4d5 [400]

If you have a skateboard and you skate into a tree on accident the same amount of force you put onto that tree when you was on the skateboard will come back at you when you bounce back

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2 years ago

A skier is accelerating down a 30.0-degree hill at 3.80 m/s^2.

Bond [772]

Answer:

ax = -3.29[m/s²]

ay = -1.9[m/s²]

Explanation:

We must remember that acceleration is a vector and therefore has magnitude and direction.

In this case, it is accelerating downwards, therefore for a greater understanding we will make a diagram of said vector, this diagram is attached.

$a_{x}=-3.8*cos(30) = -3.29 [m/s^{2}]\\ a_{y}=-3.8*sin(30) = -1.9 [m/s^{2}]$