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Wittaler [7]
3 years ago
14

A house is advertised as having 1460 square feet under roof. What is the area of this house in square meters?

Physics
2 answers:
Vladimir [108]3 years ago
8 0
1400 is the story of the president Barack Obama
Wewaii [24]3 years ago
6 0

Answer: 131.92 m

Explanation: The problem give above is a conversion problem. To convert any measurement from one unit to another, we need a relation for the original units to that of the desired unit. This relation is called the conversion factor. It is used by multiplying or dividing the factor depending on what is the unit of the original measurement. For this case, we need to convert from ft^2 to m^2. The conversion factor would be 1 foot is equal to 0.3048 m. So, we would be getting the square of the factor and then multiply to the original value.

1420 ft^2 ( 0.3048 m / 1 ft)^2 = 131.92 m

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a spherical mirror is cut in half horizontally will an image be formed by the bottom half of the mirror how
monitta

Answer:

Explanation:

the spherical mirror can form an image even if it is cut in half horizontally , but the image formed may be blurred.

pls mark as brainliest if you find it helpful

7 0
3 years ago
MARKING BRAINLIST | Which situation below would have the STRONGEST gravitational force between them?
maks197457 [2]

Case d) has the strongest gravitational force

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

a) For this pair of objects:

m1 = 10 kg

m2 = 2 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(2)}{30000^2}=1.48\cdot 10^{-18}N

b) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{30000^2}=7.41\cdot 10^{-18}N

c) For this pair of objects:

m1 = 2 kg

m2 = 2 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(2)(2)}{10000^2}=1.33\cdot 10^{-17}N

d) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{10000^2}=6.67\cdot 10^{-17}N

Therefore, the  strongest gravitational force is in case d).

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

6 0
3 years ago
An air hockey game has a puck of mass 30 grams and a diameter of 100 mm. The air film under the puck is 0.1 mm thick. Calculate
OverLord2011 [107]

Answer:

time required after impact for a puck is 2.18 seconds

Explanation:

given data

mass = 30 g = 0.03 kg

diameter = 100 mm = 0.1 m

thick = 0.1 mm = 1 ×10^{-4} m

dynamic viscosity = 1.75 ×10^{-5} Ns/m²

air temperature = 15°C

to find out

time required after impact for a puck to lose 10%

solution

we know velocity varies here 0 to v

we consider here initial velocity = v

so final velocity = 0.9v

so change in velocity is du = v

and clearance dy = h

and shear stress acting on surface is here express as

= µ \frac{du}{dy}

so

= µ  \frac{v}{h}   ............1

put here value

= 1.75×10^{-5} × \frac{v}{10^{-4}}

= 0.175 v

and

area between air and puck is given by

Area = \frac{\pi }{4} d^{2}

area  =  \frac{\pi }{4} 0.1^{2}

area = 7.85 × \frac{v}{10^{-3}} m²

so

force on puck is express as

Force = × area

force = 0.175 v × 7.85 × 10^{-3}

force = 1.374 × 10^{-3} v    

and now apply newton second law

force = mass × acceleration

- force = mass \frac{dv}{dt}

- 1.374 × 10^{-3} v = 0.03 \frac{0.9v - v }{t}

t =  \frac{0.1 v * 0.03}{1.37*10^{-3} v}

time = 2.18

so time required after impact for a puck is 2.18 seconds

3 0
3 years ago
Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her
SVETLANKA909090 [29]

Answer:

Calculate using the formula

Explanation:

velocity= displacement (m)/time(s)

1 mile =1.6km

1km=1000m

7 0
3 years ago
__________ is when all light rays bounce off an object at the same angle.
Ad libitum [116K]
Diffuse reflection have a great day

5 0
2 years ago
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