Yes the dióxido de carbono is very important
Answer: Option d. pressure increase by a factor of 3
Explanation:
P1 = P
T1 = 300k
T2 = 900K
P2 =?
Volume is constant.
P1/T1 = P2/T2
P/300 = P2/900
P2 x 300 = P x 900
P2 = (P x 900)/300
P2 = 3P
The pressure increased by a factor of 3
Limiting reactant : O₂
Mass of N₂O₄ produced = 95.83 g
<h3>Further explanation</h3>
Given
50g nitrous oxide
50g oxygen
Reaction
2N20 + 302 - 2N204
Required
Limiting reactant
mass of N204 produced
Solution
mol N₂O :

mol O₂ :

2N₂O+3O₂⇒ 2N₂O₄
ICE method
1.136 1.5625
1.0416 1.5625 1.0416
0.0944 0 1.0416
Limiting reactant : Oxygen-O₂
Mass N₂O₄(MW=92 g/mol) :

Explanation:
Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.
Reduction takes place at the cathode.
In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.
The half reaction is :

Answer:
Explanation:
the answer is two electrons im positive