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morpeh [17]
3 years ago
8

Which expression is equivalent to mn²/mn+m²n² ? a.) 1/n+m b.) n/1+m²n² c.) n/1+mn d.) 1/m²n​

Mathematics
1 answer:
ozzi3 years ago
6 0

<u>Given</u>:

The given expression is \frac{m n^{2}}{m n+m^{2} n^{2}}

We need to determine the equivalent expression.

<u>Equivalent expression:</u>

The equivalent expression can be determined by simplifying the given expression.

Thus, let us factor out the common term "mn" from the denominator.

Thus, we have;

\frac{m n^{2}}{n m(1+m n)}

Cancelling the common terms, we get;

\frac{n}{1+m n}

Thus, the equivalent expression is \frac{n}{1+m n}

Hence, Option c is the correct answer.

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Answer:

UwU

Step-by-step explanation:

UwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwU

8 0
3 years ago
PLEASE HELP 8th GRADE MATH QUESTION OVER HERE!!!
patriot [66]

The side AB measures option 2. \sqrt{20}} units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.

where (x_{1},y_{1}) are the coordinates of the first point and (x_{2},y_{2}) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), (x_{1},y_{1}) = (4, 5) and (x_{2},y_{2}) = (2, 1). Substituting these values in the distance formula, we get

d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.

So the side AB measures \sqrt{20}} units long which is the second option.

6 0
3 years ago
How to do this question
Hoochie [10]
312.5 x 13. Which is <span>4062.5. Then add 1562.5 to get 5625. So by 1998 there would be 5625 bald eagle pairs</span>
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=10-%5Cfrac%7B3y-1%7D%7B2%7D%20%3D%5Cfrac%7B6y%2B3%7D%7B11%7D" id="TexFormula1" title="10-\frac
Ghella [55]

10-\frac{3x-1}{2} =\frac{6x+3}{11}

10 = \frac{6x+3}{11} + \frac{3x-1}{2}

10 = (\frac{6x+3}{11} \times  \frac{2}{2} ) + (\frac{3x-1}{2} \times  \frac{11}{11} )

10 = ( \frac{2(6x + 3)}{22} ) + ( \frac{11(3x - 1)}{22} )

10 =  \frac{12x + 6}{22}  +  \frac{33x - 11}{22}

10 =  \frac{12x + 6 + 33x  - 11}{22}

10 =  \frac{(12 x + 33x) + (6 - 11)}{22}

10 =  \frac{45x - 5}{22}

10 \times 22 = 45x - 5

220 = 45x - 5

220 + 5 = 45x

225 = 45x

\frac{225}{45}  = x

\frac{45}{9}  = x

5 = x

7 0
2 years ago
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 3 small boxes has a t
-BARSIC- [3]

Answer:

The weight of large and small box are 18.25 kg and 13.25 kg respectively.

Step-by-step explanation:

Let the weight of large and small box are x and y respectively.

It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.

5x+3y=131                .... (1)

A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.

2x+6y=116                .... (2)

On solving (1) and (2) using graphing calculator, we get

x=18.25

y=13.25

Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.

4 0
4 years ago
Read 2 more answers
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