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Tamiku [17]
3 years ago
8

Displacement vectors of 4 km north, 2km south, 5 km north, and 5km south combine to a total displacement of A 2 km south B 16 km

south C.16 km north D 2km north?
Physics
1 answer:
Phantasy [73]3 years ago
7 0
The north vectors add up as so the south vectors.  Then subtract the two.  For north its 4 + 5 = 9.  South is 2 + 5 = 7.   Then 9-7 = 2km North (D)
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Franklin needs to ship a box with FedEx. In order to calculate his shipping costs, he needs to measure the mass of the package.
balandron [24]

Answer:

meter

Explanation:

please mark as brainlist answer

8 0
3 years ago
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You are an engineer in charge of designing a new generation of elevators for a prospective upgrade to the Empire State Building.
katen-ka-za [31]

Answer:

22.505 seconds

Explanation:

V =19.8m/s

V = a*to

t1 = 19.8/3.3

= 6seconds

Distance travelled during acceleration

= 1/2 x 3.3 x 6²

= 59.4m

X_total = x1 + x2

X2 = 373-59.4

X2 = 313.6m

t2 = x2/v

= 313.6/19.8

= 16.505

Total = 16.505 + 6

= 22.505 seconds

the minimum time in which an elevator can travel the 373 m from the ground floor is 22.505 seconds.

7 0
3 years ago
A marble resting near the edge of .90 m high table is given an initial horizontal speed of 1.24 m/s. What will be it’s horizonta
Maru [420]

Answer:

0.53 m

Explanation:

First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is h=0.90 m, the initial vertical velocity is zero, while the acceleration is g=-9.81 m/s^2, so the vertical position at time t is given by

y(t)=h-\frac{1}{2}gt^2

By demanding y(t)=0, we find the time t at which the ball reaches the ground:

0=h-\frac{1}{2}gt^2

t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(0.9 m)}{9.81 m/s^2}}=0.43 s

Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is

x=vt=(1.24 m/s)(0.43 s)=0.53 m

8 0
3 years ago
An 11.0 -W energy-efficient fluorescent lightbulb is designed to produce the same illumination as a conventional 40.0-W incandes
yarga [219]

The amount or cost that the user of the energy-efficient bulb save during 100h of use will be $0.319.

<h3>How to calculate the cost?</h3>

For the 11.0W bulb, it should be noted that the value will be:

= 11.0 × 100 × (1/1000) × 0.110

= $0.121

The 40W bulb will be:

= 40 × 100 × (1/1000) × 0.110

= $0.44

Therefore, the amount that will be saved will be:

= $0.44 - $0.121

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Learn more about cost on:

brainly.com/question/25109150

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6 0
2 years ago
How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
soldi70 [24.7K]

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J

So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.

6 0
3 years ago
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