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irakobra [83]
3 years ago
10

Special ways that animals' bodies work to help them survive in whatev

Physics
1 answer:
alexira [117]3 years ago
8 0

Answer:

Physiological – special ways that animals' bodies work to help them survive in whatever condition they're in, such as camels in the desert conserving water and being able to go days without drinking.

Explanation:

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3 years ago
What is the force on an object that accelerates at 2 m/s/s and has a mass of 120 kg
11111nata11111 [884]

Answer:

240 Newtons

Explanatiohn:

f = m × a

f = 120 × 2

f = 240 Newtons

<h3>The force is 240 Newtons</h3>
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11. A plow pushes 100 kg of snow with 300 N of force. How much is the pile of snow<br> accelerated?
Fed [463]

Answer:

Explanation:

This is an application of Newton's second Law.

Formula

F = m * a

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3 years ago
Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a
blagie [28]

Answer:

The maximum speed at which the car can safety travel around the track is 18.6m/s.

Explanation:

Since the car is in circular motion, there has to be a centripetal force F_c. In this case, the only force that applies for that is the static frictional force f_sbetween the tires and the track. Then, we can write that:

f_s=F_c

And since f_s\leq \mu N and F_c=\frac{mv^{2}}{r}, we have:

\mu N\geq \frac{mv^{2}}{r}

Now, if we write the vertical equation of motion of the car (in which there are only the weight and the normal force), we obtain:

N-mg=0\\\\\\implies N=mg

Substituting this expression for N and solving for v, we get:

\mu mg\geq \frac{mv^{2}}{r}\\\\v\leq \sqrt{\mu gr}

Finally, plugging in the given values for the coefficient of friction and the radius of the track, we have:

v\leq \sqrt{(0.42)(9.81m/s^{2})(84.0m)}\\\\v\leq 18.6m/s

It means that in its maximum value, the speed of the car is equal to 18.6m/s.

7 0
3 years ago
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Two dimensional motion is not always projectile motion. In two dimensional motion that is not projectile motion, what is not acc
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gravity is the correct answer.

4 0
4 years ago
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