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2 years ago

The metric unit of force is the

1 answer:

6 0

Newtons. Force is mass times acceleration. Mass is measured in kilograms (kg) and acceleration is measured in meters per second squared (m/s^2.) These units (kg and m/s^2) multiplied together like in the equation force equals mass times acceleration (F=ma) gives a product with Newtons as the unit.

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Describe the motion of an automobile on an east-west

Tanya [424]

Answer:

1. The automobile is traveling due east and is speeding up.

2. The car is traveling due east and is is slowing down.

3. The automobile is traveling due east at a constant speed.

4. The car is traveling due west and is slowing down.

5. The automobile is traveling due west and is speeding up.

6. The automobile is traveling due west at a constant speed.

7. The automobile is accelerating due east from rest.

8. The automobile is accelerating due west from rest.

Explanation:

The key to understanding this is:

When the acceleration and initial velocity of the automobile have the same sign (positive or negative) then the automobile is speeding up. Explained further, if acceleration and the initial velocity are both positive or they are both negative the automobile is speeding up but whenever they have opposite signs (that is acceleration is positive and initial velocity is negative or vice versa) the automobile is slowing down. When the acceleration is zero the automobile is maintaining a unform motion at a constant speed (the speed is not changing with time). The + or - sign indicates the direction of travel. In this case east is + and west is -. It is my pleasure answering this question. I hope you find it helpful. Thank you.

4 0

2 years ago

Show that (a)KE=1/2mv2

evablogger [386]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{see \: below}}}}}$

Explanation:

$\underline{ \bold{ \sf{To \: prove \: that \: kinetic \: energy = \frac{1}{2} m {v}^{2} }}}$

Let us consider, a body of mass ' m ' is lying at rest ( initial velocity = 0 ) on a smooth surface. Let a constant force F displaces this body in its own direction by a displacement ' d '. Let 'v' be it's final velocity. The work done ' W ' by the force is given by :

$\sf{W = FD}$

⇒ $\sf{W = m \: \times a \: \times s} \: \: \: \: \: \: \: \: \: ( \: ∴ \: f \: = \: ma \: ; \: s \: = d)$

⇒ $\sf{W = m \: \times \frac{v - u}{t} \times \frac{u + v}{2} \times t \: \: \: \: \: \: \: \: \: (∴ \: a = \frac{v - u}{t} and \: s = \frac{u + v}{2} \times t}$

⇒ $\sf{W = m \times \frac{ {v}^{2} - {u}^{2} }{2} }$

⇒ $\sf{W = \frac{1}{2} m {v}^{2} \: \: \: \: \: \: \: \: \: \: \: \: (since, \: initial \: velocity(u) = 0)}$

The work done becomes the kinetic energy of the body. Thus, the kinetic energy of a body of mass ' m : moving with the velocity equal to 'v ' is 1 / 2 mv²

∴ $\sf{KE= \frac{1}{2} m {v}^{2} }$

$\sf{ \underline{ \bold{ {proved}}}}$

Hope I helped!

Best regards!!

5 0

2 years ago

Make the following conversion:

katrin2010 [14]

Answer:

Kelvin to Celsius: C = K - 273 (C = K - 273.15 if you want to

6 0

1 year ago

The Density of a liquid is 1.0g/cm³. What is its density in kg/m? Show your workings clearly.

Ipatiy [6.2K]

Answer:

$\displaystyle 1 \frac{gr}{cm^3}=1,000\frac{kg}{m^3}$

Explanation:

Note: We are assuming the unit 'm' is 'm^3' to be compatible with the given unit.

Unit Conversions

Is the procedure followed to change the units of a certain magnitude to other units of the same magnitude. Example: centimeters to meters, hours to minutes, Kg to gr.

When dealing with composite units, each unit must be converted separately.

The density of some liquid is

$\displaystyle 1 \frac{gr}{cm^3}$