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Julli [10]
3 years ago
8

This reaction appears to be destroying the logs. when it is over only ash will remain, the law of conservation of mass tells us

no mass is lost. how can you explain this?
Physics
1 answer:
Advocard [28]3 years ago
7 0
The law of conservation tells us that no mass is lost. This is true because when wood burns or turns into ash, some of it is escaped as gases like carbon dioxide and water vapor into air . If we calculate the mass of these atmospheric gases that evolved when the wood turned into ash, we would find that the total mass of all these substances including the ash is equal to the log of wood.
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Which of these is NOT a chemical property of matter?
marshall27 [118]

C. Magnetism

It is a physical property, not a chemical property.

7 0
3 years ago
A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of soun
ella [17]

Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

4 0
3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.55 times a second. A tack is stuck in the tire a
earnstyle [38]

Answer:

Tangential speed = 5.72 m/s

Centripetal acceleration = 91.6\text{ m/s}{}^2

Explanation:

The tangential speed, V, is given by

v=\omega r

where \omega is the angular speed and is given by 2\pi f (f is the angular frequency or frequency of rotation)

Thus,

v=2\pi f r = 2\times3.14\times2.55\times0.357 = 5.72\text{ m/s}

The centripetal acceleration,a, is given by

a=\dfrac{v^2}{r}

a=\dfrac{5.72^2}{0.357} = 91.6\text{ m/s}{}^2

7 0
4 years ago
Read 2 more answers
Outside controlled airspace, the minimum flight visibility requirement for vfr flight above 1,200 feet agl and below 10,000 feet
nalin [4]
The least possible flight visibility prerequisite for VFR flight above 1200 feet AFL and below 10000 feet MSL for the duration of daylight hours is 1 mile in the external controlled airspace. In aeronautics, visual meteorological conditions or as called as VMC is an aviation flight group in which visual flight rules or VFR is allowed that is in circumstance in which pilot have adequate visibility to fly the aircraft sustaining visual leave-taking from terrain and other aircraft. They are the contradictory of instrument meteorological conditions. The border standards among instrument meteorological conditions and visual meteorological circumstances are recognized as the visual meteorological conditions minima and are well-defined by visibility, cloud ceilings for take offs and landing and cloud allowances.  
3 0
3 years ago
Find the frequency of a spring block system if it is doing 4 oscillation in 100s
Paha777 [63]

Answer:

.004 Hz

Explanation:

Frequeny is cycles per second. An oscillation is 1 cycle

F=cycles/sec

4/100

=0.004Hz (Hz- Hertz=1 cycle/sec)

3 0
3 years ago
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