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butalik [34]
3 years ago
11

Who no this i need help i need to pass to the next grade

Chemistry
1 answer:
Hitman42 [59]3 years ago
7 0

Exothermic reactions is where  energy is released. Exothermic reactions are reactions that release energy into the environment in the form of heat. Exothermic reactions feel warm or hot or may even be explosive.

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E. a small yellow ball that represents the Sun

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key word on the question, 'physical'

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Compare a mixture and a compound. How are they alike?
harina [27]

Answer:

1.Difference.

Mixtures are physically combined and can be separated by physical means while compounds are chemically combined and are separated by chemical means.

2.Mixtures do not have mixed boiling and melting points while compounds have mixed boiling and melting points.

2.Similarity.

Both mixtures and compounds are composed of two or more substances or elements combined.

Both can be separated.

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3 years ago
Why is it the principle about the relationship between mass and volume always true of substance, but not always true of mixtures
Xelga [282]

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For pure substances, the mass and volume will always be the same or will always change the same way because all substance are the same throughout.

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7 0
1 year ago
Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo
Romashka-Z-Leto [24]

Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

Volume of a cone:

  • \displaystyle V=\frac{1}{3} \pi r^2 h

We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

  • \displaystyle V =\frac{1}{3} \pi (5h)^2 h  
  • \displaystyle V =\frac{1}{3} \pi \ 25h^3

Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
  • \displaystyle \frac{dV}{dt}  =25 \pi h^2 \ \frac{dh}{dt}

Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
  • \displaystyle 10 = 100 \pi  \ \frac{dh}{dt}  

Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
  • \displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0
3 years ago
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