What function do the wind-driven currents play in the transport of heat energy in the oceans?

1 answer:

7 0

Wind driven currents create in the equatorial and warm zones of the earth’s oceans. The currents then transmit the warm water north, where the heat in the water is misplaced to the colder atmosphere. In the instance of the Gulf Stream, this transmission of heat to the air warms up England and Europe.
As the water cools, its' density upsurges because of chilling and increasing salinity. This cold water drops to the bottom of the ocean, where it is then stimulated by another current back south, similar to a train creating a big circuit.

You might be interested in

Approximately what percent of the Moon’s surface is illuminated on a new-moon day? A) 0% B) 20% C) 50% D) 100%

Sergeeva-Olga [200]

At New Moon the percent illuminated is 0; at First and Last Quarters it is 50%; and at Full Moon it is 100%. During the crescent phases the percent illuminated is between 0 and 50% and during gibbous phases it is between 50% and 100%.
so it depends on the phase

3 0

3 years ago

Read 2 more answers

Before you conduct your experiment, you need to form a hypothesis. A hypothesis is a prediction of what you think will happen in

Stolb23 [73]

Example: A apple rotting.

If I put my apple in a fridge, then it would not rot as fast because it is in a cooled area. (example)

Hope it helps! Brainiest Answer would be amazing!

5 0

3 years ago

The magnitude of the net electrical force acting on the +6 µC charge, rounded to the tenths place, is N.

Lyrx [107]

Electrical force is the repulsive or attractive force of attraction between any two charged bodies. it is possible to calculate electric force on anything that runs on batteries or uses a plug. Its net effect can be explained using newtons law of motion like any force.
From the coulombs law; F = k (q1║q2)/ r²
Where k = 9 ×10∧9 N.m².C∧-2, r12= 0.285m, q2= +6μC and q1 = 4.86 nC
substituting values in the equation
the net electrical force acting on the +6ц C charge is 5.4 N.

8 0

3 years ago

Read 2 more answers

A spring-loaded toy gun is used to shoot a ball of mass 1.5 kg straight up in the air, as shown. The spring has spring constant

asambeis [7]

Answer:

Part a)

U = 15.5 J

Part b)

h = 1.05 m

Part c)

v = 4.55 m/s

Explanation:

Part a)

Initial potential energy stored in the spring is given by

$U = \frac{1}{2}kx^2$

now we have

$k = 777 N/m$

x = 20.0 cm

now from above formula we will have

$U = \frac{1}{2}(777)(0.20)^2$

$U = 15.5 J$

Part b)

By mechanical energy conservation law we can say that initial spring potential energy stored = final gravitational potential energy at the top position

$\frac{1}{2}kx^2 = mgh$