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3 years ago

The human activities in two locations are described below:

Physics

2 answers:

Bogdan [553]3 years ago

5 0

Air pollution level is higher in Location B, because poisonous fumes are produced when coal burns.

CaHeK987 [17]3 years ago

3 0

Answer:

Statement (c) is true.

Explanation:

It is given that, the human activities in two locations are described below:

Location A: Wind turbines used for generating electricity

Location B: Coal used to generate electricity

From the given options the correct statement is (c) i.e. "Air pollution level is higher in Location B because poisonous fumes are produced when coal burns". It is because whenever coal is burnt, a number of toxins and pollutants such as nitrogen oxides, mercury, lead etc which causes several diseases.

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It would take at less 10 minte i guess this the right awnser

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3 years ago

0.250 moles of gas are in a piston.The gas does 109 J of work while 240 J of heat are added. What is the change in internal ener

irina [24]

Answer:

+131Joules

Explanation:

Energy can be expressed using below expresion.

ΔE = (q + w).........eqn(1)

q will be + be if heat is gained hence, q= 240 J

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Then substitute into eqn(1)

Change in Internal energy=

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3 years ago

A +71 nC charge is positioned 1.9 m from a +42 nC charge. What is the magnitude of the electric field at the midpoint of these c

viva [34]

Answer:

The net Electric field at the mid point is 289.19 N/C

Given:

Q = + 71 nC = $71\times 10^{- 9} C$

Q' = + 42 nC = $42\times 10^{- 9} C$

Separation distance, d = 1.9 m

Solution:

To find the magnitude of electric field at the mid point,

Electric field at the mid-point due to charge Q is given by:

$\vec{E} = \frac{Q}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}$

$\vec{E} = \frac{71\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}$

$\vec{E} = 708.03 N/C$

Now,

Electric field at the mid-point due to charge Q' is given by:

$\vec{E'} = \frac{Q'}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}$

$\vec{E'} = \frac{42\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}$

$\vec{E'} = 418.84 N/C$

Now,

The net Electric field is given by:

$\vec{E_{net}} = \vec{E} - \vec{E'}$

$\vec{E_{net}} = 708.03 - 418.84 = 289.19 N/C$

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3 years ago

Part A Magnetic field lines form closed loops Magnetic field lines form closed loops Around and through bar magnets. Through cur

alex41 [277]

Answer:

Magnetic field lines form closed loops around current carrying straight wires.

Explanation:

Magnetic field lines is known to form closed loop (which also serves as a bar magnet) around current carrying conductor in a magnetic field. This direction of the loop around the conductor either clockwise or anticlockwise will determine the direction of current in the conductor.

This directions can be determined using the Maxwell cockscrew or clenched fist rule.

According to clenched fist rule which states if the conductor is grasp with the right hand, the curled finger will point in the direction of the magnetic field and the thumb will point in the direction of the current.

Note that the magnetic field lines around the conductor also behaves like a bar magnet.

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3 years ago

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tresset_1 [31]

I believe that it is called refracting...

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