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irakobra [83]
3 years ago
10

The human activities in two locations are described below:

Physics
2 answers:
Bogdan [553]3 years ago
5 0
Air pollution level is higher in Location B, because poisonous fumes are produced when coal burns.
CaHeK987 [17]3 years ago
3 0

Answer:

Statement (c) is true.

Explanation:

It is given that, the human activities in two locations are described below:

Location A: Wind turbines used for generating electricity

Location B: Coal used to generate electricity

From the given options the correct statement is (c) i.e. "Air pollution level is higher in Location B because poisonous fumes are produced when coal burns". It is because whenever coal is burnt, a number of toxins and pollutants such as nitrogen oxides, mercury, lead etc which causes several diseases.

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The materials that made up their solar nebula can be categorized into the four general type as follows. Rank these materials fro
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Answer: Hydrogen and Helium > Hydrogen compounds > Rocks > Metals

Explanation: The solar nebular system contains 98% Light Gases of both Hydrogen and Helium (produced in the Big Bang); followed by 1.4% of Hydrogen Compounds including water, methane, and ammonia; then followed by 0.4% of Rocks like Silicates; and lastly 0.2% of Metals including Iron, Nickel and Aluminium.

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3 years ago
What do you need to verify in a patient's profile? A. Name, history of illness, medication, dose, strength, frequency B. Name, a
Lubov Fominskaja [6]
Hey there friend :)

I would go with Choice A

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3 0
4 years ago
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Two bowling balls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravita
12345 [234]

Answer:

6.49 x 10^-8 N

Explanation:

formula is

F= G * ((m1 * m2)/r^2)

F = 6.67x10^-11 * ((6.8*6.8/.218)

F = 6.49 x 10^-8 Newtons

3 0
3 years ago
A motorcycle that is slowing down uniformly covers 2.0 successive km in 80 s and 120 s, respectively. Calculate (a) the accelera
8090 [49]

Answer:

acceleration = -0.042 m/s²

velocity at beginning =  14.167 m/s

velocity at  end = 5.7183 m/s

Explanation:

given data

distance d1 = 1 km

distance d2 = 2 km

time  t1 = 80 s

time t2 = 120 s + 80s = 200 s

to find out

acceleration and velocity at beginning and end

solution

we apply here law of motion that is

d = vt + 1/2×at²    

put value

1000 = v(80) + 1/2×a(80)²           ........................1

and

2000 = v(200) + 1/2×a(200)²      ........................2

so from equation 1 and 2 we get a and v

a = -0.042 m/s² and

v = 14.167 m/s

so by kinematic final velocity will be

V² = v² + 2ad

V² = (14.167)² + 2×(-0.042)×(2000)

V²  = 32.70

V = 5.7183 m/s

so

acceleration = -0.042 m/s²

velocity at beginning =  14.167 m/s

velocity at  end = 5.7183 m/s

8 0
3 years ago
Mgbr2 how many atoms of each element are in this compound?
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1 atom of Mg(Magnesium) and 2 atoms of Br(Bromine)
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