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irakobra [83]
3 years ago
10

The human activities in two locations are described below:

Physics
2 answers:
Bogdan [553]3 years ago
5 0
Air pollution level is higher in Location B, because poisonous fumes are produced when coal burns.
CaHeK987 [17]3 years ago
3 0

Answer:

Statement (c) is true.

Explanation:

It is given that, the human activities in two locations are described below:

Location A: Wind turbines used for generating electricity

Location B: Coal used to generate electricity

From the given options the correct statement is (c) i.e. "Air pollution level is higher in Location B because poisonous fumes are produced when coal burns". It is because whenever coal is burnt, a number of toxins and pollutants such as nitrogen oxides, mercury, lead etc which causes several diseases.

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2 years ago
A uniform electric field with a magnitude of 5750 N/C points in the positive x direction. Find the change in electric potential
castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge q=+10.5\times10^{-6}\ C

Distance = 5.50 cm

(a). When the charge is moved in the positive x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot d

\Delta U=-q(E\cdot d)

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}

\Delta U=-3.32\times10^{-3}\ J

The change in electric potential energy  is -3.32\times10^{-3}\ J

(b). When the charge is moved in the negative x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot (-d)

\Delta U=-q(E\cdot (-d))

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})

\Delta U=3.32\times10^{-3}\ J

The change in electric potential energy  is 3.32\times10^{-3}\ J

Hence, This is the required solution.

3 0
3 years ago
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