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RoseWind [281]
3 years ago
7

80.5 J of heat are added to 0.222 moles of a diatomic gas. It expands, doing work, and the temperature goes up by 12.0 K. How mu

ch work did the gas do? (Unit=J)
Physics
1 answer:
OLga [1]3 years ago
4 0

The work done by the gas is 25.1 J

Explanation:

The change in internal energy of a diatomic gas is given by the equation

\Delta U = \frac{5}{2}nR\Delta T

where:

n is the number of moles

R is the gas constant

\Delta T is the change in temperature

For the gas in this problem:

n = 0.222 mol

R=8.314 J/mol K

\Delta T=12.0 K

Substituting,

\Delta U = \frac{5}{2}(0.222)(8.314)(12.0)=55.4 J

Now we can find the work done by the gas using the 1st law of thermodynamics:

\Delta U = Q-W

where:

Q = +80.5 J is the heat added to the gas

\Delta U = +55.4 J is the change in internal energy

W is the work done by the gas

And solving for W,

W=Q-\Delta U = 80.5-(55.4)=25.1 J

And since it is positive, it means that the work is done BY the gas.

Learn more about thermodynamics:

brainly.com/question/4759369

brainly.com/question/3063912

brainly.com/question/3564634

#LearnwithBrainly

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Answer:

v= 26.70 m/seg

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De acuerdo a la segunda ley de Newton

∑ F  =  m*a

∑ Fx  =  m* a(x)             ∑ Fy  =  m* a(y)

También sabemos que el coeficiente de roce dinámico es:

  μ  = 0.2 = F(r)/N            siendo N la fuerza normal.

Si descomponemos la fuerza P = mg  =  20Kg* 9.8m/seg²

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Py  =  P* cos30  =  196* √3/2  =  98*√3

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La sumatoria sobre el eje y es :

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98 -  19.6*√3  =  m*a

98  -  33.52  = m*a

a =  (98  -  33.52 ) / 20

a = 3.22 m/seg²

Para calcular la velocidad del trineo al pié del plano, sabemos que al pié del plano el trineo ha recorrido 80 m, y que de cinemática

v²  =  v₀²  +  2*a*d             ( se pueden chequear unidades para ver la consistencia de la ecuación  v  y  v₀    vienen dados en m/seg  entonces  v²  y  v₀²  vienen en m²/seg²,  el producto de a (m/seg²) por la distancia d (m) resulta en m²/seg²  entonces es consistente la relación

v²   =  0   +  2*3.22*80       ( la velocidad inicial es cero)

v²  = 515.2  m²/seg²

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