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lakkis [162]
3 years ago
5

There are free body diagrams in the picture, number (#). Which of the diagram(s) shows an object with a net force right?

Physics
2 answers:
zubka84 [21]3 years ago
7 0

Answer:

Figure (4)

Explanation:

In this case 4 free body diagrams are shown. In Figure (1), there is no normal force acting on the object. It will accelerate in downwards direction.

In figure (2), the box is balanced. All forces cancel out each other.

In figure (3), the box is not balanced. The horizontal forces cancel out each other while the downward force is greater than the greater than upward force. The object will accelerate in downward direction.

In figure (4), no normal force is acting. In this case, the force towards right is more than the force towards left. So, the object will move towards right.

Hence, the correct option is (c) " figure (4) only".

ryzh [129]3 years ago
6 0
4 only diagram net Force
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W is the work done on the system, and K, U, and Eth are the kinetic, potential, and thermal energies of the system, respectively
MArishka [77]

Answer:

1) a block going down a slope

2) a) W = ΔU + ΔK + ΔE, b) W = ΔE, c)  W = ΔK, d) ΔU = ΔK

Explanation:

In this exercise you are asked to give an example of various types of systems

1) a system where work is transformed into internal energy is a system with friction, for example a block going down a slope in this case work is done during the descent, which is transformed in part kinetic energy, in part power energy and partly internal energy that is represented by an increase in the temperature of the block.

2)

a) rolling a ball uphill

In this case we have an increase in potential energy, if there is a change in speed, the kinetic energy also increases, if the change in speed is zero, there is no change in kinetic energy and there is a change in internal energy due to the stationary rec in the point of contact

 W = ΔU + ΔK + ΔE

b) in this system work is transformed into internal energy

      W = ΔE

c) There is no friction here, therefore the work is transformed into kinetic energy

    W = ΔK

d) if you assume that there is no friction with the air, the potential energy is transformed into kinetic energy

      ΔU = ΔK

7 0
3 years ago
A basketball star exerts a force of 3225 n (average value) upon the gym floor in order to accelerate his 76.5-kg body upward. de
ryzh [129]
F = m . g  = 76.5 x 9..8 = 749.7
Net Force = 3225 - 749.7 = 2475.3

F = m.a
2475.3 = 76.5 a

a  = 32.35



V = at + v1
V = at + 0
V = 32.35 x 0.15
V = 4.8525

Hope this helps

8 0
3 years ago
1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-3
Rudiy27

Answer:

 E = 2,964 10⁻¹⁹ J

Explanation:

The energy of the photons is given by the Planck relation

          E = h f

the speed of light is related to wavelength and frequency

          c = λ f

we substitute

          E = h c /λ

let's reduce the magnitude to the SI system

          λ = 671 nm = 671 10⁻⁹ m

let's calculate

          E = 6.63 10⁻³⁴ 3 10⁸ /671 10⁻⁹

          E = 2,964 10⁻¹⁹ J

6 0
3 years ago
What is the difference between a negative feedback system and a positive feedback system?
Anni [7]

Answer:

D

Explanation:

The negative feedback is responsible for maintaining equilibrium (stability) in a system as it lessens effects, which is contrary to positive feedback which increases reaction and moves a system further away from equilibrium (stability), It does so by amplifying the effects of a product or event and occurs when something needs to happen quickly. e.g

  • Insulin lowers down blood sugar levels, so when the body detects that it has too much sugar, the pancreas is prompted to release insulin and only stops when balance is achieved; hence, negative feedback.  
  •  When there is a tear on the skin, a chemical is released. This chemical causes platelets in the blood to activate, hence they release a chemical which signals more platelets to activate, until the wound is clotted, positive feedback.

7 0
3 years ago
The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

f(t)=-16t^2 +238t+3

Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
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