Answer:
numbers = 1:1:100;
for num=numbers
remainder3 = rem(num,3);
remainder5 = rem(num,5);
if remainder3==0
disp("Yee")
else
if remainder3 == 0 && remainder5 == 0
disp ("Yee-Haw")
else
if remainder5==0
disp("Haw")
else
disp("Not a multiple of 5 or 4")
end
end
end
end
Explanation:
- Initialize the numbers variable from 1 to 100.
- Loop through the all the numbers and find their remainders.
- Check if a number is multiple of 5, 3 or both and display the message accordingly.
Answer:
D.
to create a test environment
Explanation:
After releasing it will be "production"
Answer:
binary computer natural language
Answer:
1) if "<table>" is an option then that's the answer
2) <HTML>
3) <tr>
4) border-collapse collapse
5) <caption>
Explanation:
Currently studying HTML and these are the tags I'm familar with.
Computers are broadening horizons of learning and cutting back on limitations. practically all the knowledge of the worls is only a few clicks away
