Because the molecules are more spread apart.
(gas spread)
Answer:
4.41
Explanation:
Step 1: Write the balanced equation
CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)
Step 2: Calculate the respective concentrations
![[CO]_i = \frac{0.500mol}{5.00L} = 0.100M](https://tex.z-dn.net/?f=%5BCO%5D_i%20%3D%20%5Cfrac%7B0.500mol%7D%7B5.00L%7D%20%3D%200.100M)
![[H_2]_i = \frac{1.500mol}{5.00L} = 0.300M](https://tex.z-dn.net/?f=%5BH_2%5D_i%20%3D%20%5Cfrac%7B1.500mol%7D%7B5.00L%7D%20%3D%200.300M)
![[H_2O]_{eq} = \frac{0.198mol}{5.00L} = 0.0396M](https://tex.z-dn.net/?f=%5BH_2O%5D_%7Beq%7D%20%3D%20%5Cfrac%7B0.198mol%7D%7B5.00L%7D%20%3D%200.0396M)
Step 3: Make an ICE chart
CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)
I 0.100 0.300 0 0
C -x -3x +x +x
E 0.100-x 0.300-3x x x
Step 4: Find the value of x
Since the concentration at equilibrium of water is 0.0396 M, x = 0.0396
Step 5: Find the concentrations at equilibrium
[CO] = 0.100-x = 0.100-0.0396 = 0.060 M
[H₂] = 0.300-3x = 0.300-3(0.0396) = 0.181 M
[CH₄] = x = 0.0396 M
[H₂O] = x = 0.0396 M
Step 6: Calculate the equilibrium constant (Kc)
![Kc = \frac{[CH_4] \times [H_2O] }{[CO] \times [H_2]^{3} } = \frac{0.0396 \times 0.0396 }{0.060 \times 0.181^{3} } = 4.41](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BCH_4%5D%20%5Ctimes%20%5BH_2O%5D%20%7D%7B%5BCO%5D%20%5Ctimes%20%5BH_2%5D%5E%7B3%7D%20%7D%20%3D%20%5Cfrac%7B0.0396%20%5Ctimes%200.0396%20%7D%7B0.060%20%5Ctimes%200.181%5E%7B3%7D%20%7D%20%3D%204.41)
Answer:
A.
Liquid
B.
Gas
C.
Gas
D.
Solid
E.
Liquid.
Explanation:
Solids have definite shape and volume and vibrate around a fixed position. Its relative intermolecular forces are very strong which holds its particles in a fixed position.
Liquids takes the shape of the container, that is no definite shape, has fixed volume and its particles move freely but are still attached to each other due to its mildly strong intermolecular forces.
Gases has no shape nor volume but it is highly compressible while its particles move freely in random paths.
Answer:
Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)
Explanation:
Let's consider the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II) chloride and aqueous lithium nitrite.
Pb(NO₂)₂(aq) + LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)
This is a double displacement reaction. We will start balancing Cl by multiplying LiCl by 2.
Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)
Now, we have to balance Li by multiplying LiNO₂ by 2.
Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)
The equation is now balanced.
Answer: THE ANSWER IS OZONE WEEEE a layer in the earth's stratosphere at an altitude of about 6.2 miles (10 km) containing a high concentration of ozone, which absorbs most of the ultraviolet radiation reaching the earth from the sun.
Explanation:
