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xz_007 [3.2K]
3 years ago
8

What is the volume of 15.0 grams of H2S at STP

Chemistry
2 answers:
den301095 [7]3 years ago
7 0
1 mole of any gas under STP has volume 22.4 L.
Molar mass M(H2S) = 2M(H) + M(S)= 2*1.0 +32.1=34.1 g/mol
15g * 1mol/34.1g= 0.440 mol
0.440 mol*1L/22.4L= 9.85 L 
<span> The volume of 15.0 grams of H2S at STP is 9.85 L.</span>

kicyunya [14]3 years ago
6 0

Answer:

9.86 lH_ {2}S

Explanation:

STP means standard conditions of temperature and pressure and under these conditions, one mole of any substance occupies a volume of 22.4 l.

We have 15gH_ {2} to calculate the number of mols you must calculate the molecular mass of the compound.

H 2 (1g / mol)

S 32 g / mol(32+2) g / mol = 34g / mol H_ {2}S

15g H_{2}S \cdot \frac{1 mol H_ {2}S}{34g H_ {2}S} = 0.44 mol H_ {2}S

Now we calculate the volume occupied by 0.44 mol H_ {2}S

0.44 molH_ {2}S \cdot \frac{22.4 l H_ {2}S}{1mol H_ {2}S}  = 9.86lH_ {2}S

the volume of 15.0 g of H_{2}S is <em>9.86l. </em>

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