All categories

3 years ago

Why are nonmetals more likely to react with eachother by sharing electrons

Physics

2 answers:

RideAnS [48]3 years ago

8 0

The answer is; non-metals have a high ionization energy

This means that it would take more energy to dislodge an electron from the valence orbital than it would take to do the same to a metal atom. Therefore it would be easier to share electrons for non-metals while it would be easier to lose an electron for metals to reach a stable electron configuration.

yarga [219]3 years ago

5 0

Answer:

non-metals have a high ionization energy

Explanation:

You might be interested in

1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential

cupoosta [38]

<h3>Answer:</h3>

$\displaystyle U_s = 0.6 \ J$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Physics</u>

<u>Energy</u>

Elastic Potential Energy: $\displaystyle U_s = \frac{1}{2} k \triangle x^2$

U is energy (in J)
k is spring constant (in N/m)
Δx is displacement from equilibrium (in m)

<h3>Explanation:</h3>

<u>Step 1: Define</u>

k = 7.50 N/m

Δx = 0.40 m

<u>Step 2: Find Potential Energy</u>

Substitute in variables [Elastic Potential Energy]: $\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2$
Evaluate exponents: $\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)$
Multiply: $\displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)$
Multiply: $\displaystyle U_s = 0.6 \ J$

6 0

3 years ago

Two horizontal forces are exerted on a large crate. The first force is 317 N to the right. The second force is 173 N to the left

DENIUS [597]

Answer:

A. Refer to the figure.

B. The net force acting on the crate is

$F_{net} = F_1 - F_2 = 317 - 173 = 144N$

C. We should first find the acceleration of the crate using the following kinematics equation:

$v = v_0 + at\\6.5 = 0 + 5a\\a = 1.3 m/s^2$

Mass of the crate can be found by Newton’s Second Law:

$F = Ma\\M = F/a = 144/1.3 = 110.7 kg$

7 0

4 years ago

A hockey puck slides across the ice with an initial velocity of 7.3 m/s .It has a decleration of 1.1 m/s and is traveling toward

sashaice [31]

Answer:

t = 6.63 s

Explanation:

Given that,

Initial velocity of the puck, u = 7.3 m/s

Deacceleration of the puck, a = -1.1 m/s²

Distance traveled, d = 5 m

We need to find the time the goalie have to stop the puck. Using equation of motion.

v = u +at

v = 0 (stops)

So,

$u=-at\\\\t=\dfrac{u}{-a}\\\\t=\dfrac{7.3}{-(-1.1)}\\\\t=6.63\ s$

So, the required time is 6.63 seconds.

6 0

3 years ago

Where do glaciers form

Yuki888 [10]

Glaciers<span> begin to </span>form<span> when snow remains in the same area year-round, where enough snow accumulates to transform into ice. Each year, new layers of snow bury and compress the previous layers. This compression forces the snow to re-crystallize, forming grains similar in size and shape to grains of sugar.</span>

3 0

3 years ago

Read 2 more answers

A uniform metal tube of length 5m and mass 9kg is suspended by two vertical wires attached at 50cm and 150cm respectively from t

Elena-2011 [213]

Answer:

force (tension) of 29.4 N (upward) in 100 cm

force (tension) of 58.4 N (upward) in 200 cm

Explanation:

Given:

Length of tube = 5 m (500 cm)

Mass of tube = 9

Suspended vertically from 150 cm and 50 cm.

Computation:

Force = Mass × gravity acceleration.

Force = 9.8 x 9

Force = 88.2 N

So,

Upward forces = Downward forces

D1 = 150 - 50 = 100 cm

D2 = 150 + 50 = 200 cm

And F1 = F2

F1 x D1 = F2 x D2

F1 x 100 = F2 x 200

F = 2F

Total force = Upward forces + Downward forces

3F = 88.2

F = 29.4 and 2F = 58.8 N

force (tension) of 29.4 N (upward) in 100 cm

force (tension) of 58.4 N (upward) in 200 cm

4 0

4 years ago