All categories

3 years ago

What is the magnitude of a rope that is being polled 300n to the left and 425n to the right

Physics

1 answer:

Rudik [331]3 years ago

4 0

Answer:

FT = 125 [N], to the right

Explanation:

Both forces are characterized by being vectors, and these are applied in opposite directions so the difference between them will be the result of the sum of the forces.

FL = 300 [N]

FT = 425 [N]

FT = Total force

FT = 425 - 300 = 125 [N]

Since the magnitude of the force is positive, we conclude that the resultant of these forces is to the right.

You might be interested in

In this problem you will consider the balance of thermal energy radiated and absorbed by a person.Assume that the person is wear

Viefleur [7K]

Answer: $P=14.6 W$

Explanation:

According to the Stefan-Boltzmann law for real radiating bodies:

$P=\sigma A \epsilon T^{4}$ (1)

Where:

$P$ is the energy radiated (in Watts)

$\sigma=5.67(10)^{-8}\frac{W}{m^{2} K^{4}}$ is the Stefan-Boltzmann's constant.

$A$ is the Surface area of the body

$T=30\°C + 273.15= 303.15 K$ is the effective temperature of the body (its surface absolute temperature) in Kelvin

$\epsilon=0.6$ is the body's emissivity

On the other hand, we are told the human body is roughly approximated to a cylinder of length $L=2.0m$ and circumference $C=0.8m$ .

The circumference of a circle is: $C=0.8m=2 \pi r$ where $r$ is the radius. Hence $r=\frac{0.8m}{2 \pi}=0.1273 m$ .

Now we have to input this value for $r$ in the Area of a cylinder formula:

$A=\pi r^{2}L$

$A=\pi (0.1273 m)^{2}(2 m)$

$A=0.0509 m^{2}$ (2)

Substituting (2) in (1):

$P=(5.67(10)^{-8}\frac{W}{m^{2} K^{4}}) (0.0509 m^{2}) (0.6) (303.15 K)^{4}$ (3)

Finally:

$P=14.62 W \approx 14.6 W$

5 0

3 years ago

Despite a very strong wind, a tennis player

Gnoma [55]

Answer:

Option 5. 1 and 3

Solution:

The only forces acting on the tennis ball after it has left contact with the racquet and the instant before it touches the ground are the force of gravity in the downward direction and the force by the air exerted on the ball.

The ball after it left follows the path of trajectory and as it moves forward in the horizontal direction the force of the air acts on it.

In the whole projectile motion of the ball, the acceleration due to gravity acts on the ball thus the force of gravity acts on the ball in the downward direction before it hits the ground.

6 0

4 years ago

A charge Q experiences no net force at a particular point in space. Which of the following situations described below must ALWAY

laila [671]

Answer:

-There are no other charges nearby.

Explanation:

-There are no other charges nearby.

If there is no net charge in nearby space then the force on this charge will be ZERO

-If there are other charges nearby, they must all have the same sign as Q.

There there is nearby charge of same sign then it will have repulsion force on Q

-If there are other charges nearby, they must all have the opposite sign of Q.

if there is nearby charge of opposite sign then the force must be attraction force.

-If there are other charges nearby, the total positive charge must equal the total negative charge.

If there exist two type of charges nearby then there may exist either attraction or repulsion force on it

8 0

4 years ago

1 Point

fenix001 [56]

Answer:

D. The friction force increases by 9600 N.

Explanation:

Frictional force is directly proportional to kinetic coefient of friction.

6 0

4 years ago

What is the most dense thing in the world

Mashcka [7]

Any lump of osmium is. Iridium and gold are also very close.

7 0

3 years ago

Read 2 more answers