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Aneli [31]
3 years ago
10

NaCl has a Hfus = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely? 24.3 g 82.7

g 1,407.1 g 1,417.7 g
Chemistry
2 answers:
alina1380 [7]3 years ago
4 0
Hello.

The answer is  1417.7

Its 1417.7 grams becasue you have  to convert the moles to grams.


<span /><span><span>A mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.023 X 1023).

</span><span>a coherent, typically large body of matter with no definite shape.

Have a nice day</span></span>
brilliants [131]3 years ago
3 0

Answer : The mass of the sample of NaCl will be, 1417.7 grams.

Explanation : Given,

\Delta H_{fusion}=30.2kJ/mol

This means that,

As, 1 mole of sample of NaCl has an enthalpy of fusion = 30.2 kJ

And, 1 mole of NaCl has the mass = 58.44 grams

As, 30.2 kJ of heat is needed for a mass 58.44 grams of NaCl

So, 732.6 kJ of heat will be needed for = \frac{58.44g}{30.2kJ}\times 732.6 kJ=1417.65\approx 1417.7 grams of NaCl.

Hence, the mass of sample of NaCl will be, 1417.7 grams.

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How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?
Andrew [12]

Answer:

55.9 g KCl.

Explanation:

Hello there!

In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

m=\frac{mol}{kilograms}

Thus, solving for the moles of solute, we obtain:

mol=m*kilograms

Since the density of water is 1 kg/L, we obtain the following moles:

mol=0.500mol/kg*1.50kg\\\\mol=0.75mol

Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

0.75mol*\frac{74.5513g}{1mol}\\\\55.9g \ KCl

Regards!

4 0
3 years ago
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BlackZzzverrR [31]
Mg+O2=MgO
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3 0
3 years ago
How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?
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Answer:

17.5 g

Explanation:

Given data

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The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl

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Explanation:

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Answer:

The volume of the liquid should be measured before it is heated.  

Explanation:

Because During an experiment to test how a variable changes a substance, it is important to first observe and record the characteristics of the substance before the variable is introduced. In this case, the variable is heat energy.  

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