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Aneli [31]
3 years ago
10

NaCl has a Hfus = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely? 24.3 g 82.7

g 1,407.1 g 1,417.7 g
Chemistry
2 answers:
alina1380 [7]3 years ago
4 0
Hello.

The answer is  1417.7

Its 1417.7 grams becasue you have  to convert the moles to grams.


<span /><span><span>A mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.023 X 1023).

</span><span>a coherent, typically large body of matter with no definite shape.

Have a nice day</span></span>
brilliants [131]3 years ago
3 0

Answer : The mass of the sample of NaCl will be, 1417.7 grams.

Explanation : Given,

\Delta H_{fusion}=30.2kJ/mol

This means that,

As, 1 mole of sample of NaCl has an enthalpy of fusion = 30.2 kJ

And, 1 mole of NaCl has the mass = 58.44 grams

As, 30.2 kJ of heat is needed for a mass 58.44 grams of NaCl

So, 732.6 kJ of heat will be needed for = \frac{58.44g}{30.2kJ}\times 732.6 kJ=1417.65\approx 1417.7 grams of NaCl.

Hence, the mass of sample of NaCl will be, 1417.7 grams.

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(a) adding 0.050 mol of HCl

Explanation:

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In the buffer:

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<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.

(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>

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