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Nikolay [14]
3 years ago
14

The specific kinetic energy of a moving mass is given by ke = V2/2, where V is the velocity of the mass. Determine the specific

kinetic energy of a mass whose velocity is 200 ft/s, in Btu/lbm.
Physics
1 answer:
navik [9.2K]3 years ago
5 0

Answer:

0.799Btu/lbm

Explanation:

Data given

velocity, v= 200ft/s

Since the formula to define the the kinetic energy is

KE=v^{2}/2

where v=velocity and the final answer expressed in Btu/lbm

we just substitute the value of the velocity into the equation and we arrive at

KE=(200ft/s)^{2}/2\\KE=20,000ft^{2}/s^{2}

Now we convert to Btu/lbm

since

1 Btu/lbm=25,037ft^{2}/s^{2}\\

then

20000/25037\\=0.799Btu/lbm

Hence the kinetic energy in is 0.799Btu/lbm

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2 years ago
On what two properties of a material does its density depend on?
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4 0
3 years ago
What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.20 m whose potential is 240
Lady bird [3.3K]

Answer:

(a) charge q=5.33 nC

(b) charge density σ=10.62 nC/m²

Explanation:

Given data

radius r=0.20 m

potential V=240 V

coulombs constant k=9×10⁹Nm²/C²

To find

(a) charge q

(b) charge density σ

Solution

For (a) charge q

As

V_{potential}=kq/r\\ q=rV_{potential}/k\\q=\frac{(0.20)(240)}{9*10^{9} }\\ q=5.333*10^{-9}C\\or\\ q=5.33nC

For (b) charge density

As charge density σ is given as:

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σ=(5.333×10⁻⁹) / (4π×(0.20)²)

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