Answer:
In a circuit ,<u> VOLTAGE </u>can be said to be the "source" or the "push of electrons". This push then creates what is known as a <u> CURRENT , </u>which is the flow of electric charge through the circuit. This flow can the slowed down or restricted by <u>RESISTOR </u>, and this is also what can be harnessed in order to use electric <u>ENERGY </u>.
Explanation:
Voltage:
It is the 'push' that causes charges to move in a wire or other electrical conductor, also it is a Source input to the electric circuit.
Measured in Volts.
Current:
An electric current is the rate of flow of electric charge from a point or through a region.
Measured in Ampere.
Resistor:
Resistor is used to resist the flow of charge or to resist the current called as Resistance.
Measured in Ohms.
Electric Energy:
Electrical energy is a form of energy resulting from the flow of electric charge.
Measured in Joules.
In a circuit , voltage can be said to be the "source" or the "push of electrons". This push then creates what is known as a current, which is the flow of electric charge through the circuit. This flow can the slowed down or restricted by resistor, and this is also what can be harnessed in order to use electric energy.
If you mean the SI Unit of GPE, the answer is J for Joules.
if that's not the question being asked, i would need a little more elaboration please :)
Answer:
a = F/m
Explanation:
So we have to isolate a, in order to do this we need to move m to the other side, and we do that by diving both sides by m, resulting in a = F/m
The given question is incomplete. The complete question is as follows.
A parallel-plate capacitor has capacitance 
= 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.
What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 
V/m?
Explanation:
It is known that relation between electric field and the voltage is as follows.
V = Ed
Now,
Q = CV
or, Q = 
Therefore, substitute the values into the above formula as follows.
Q =
= 
= 
Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is .
