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dedylja [7]
3 years ago
11

Iron (III) oxide reacts with carbon monoxide producing iron metal and carbon dioxide. How much grams of iron is produced from 74

9 g of iron (III) oxide
Chemistry
1 answer:
Katarina [22]3 years ago
3 0

Answer:

389.48g of Fe

Explanation:

This is a stoichiometric reaction. First write a balanced equation of reaction: Fe2O3+3CO==>2Fe+3CO2

Since Fe2O3 and Fe are concerned with, calculate there masses in the balanced equation

Taking Molar mass of Fe and O to be 26 and 16 respectively.

Fe2O3 = (2×26) + (3×16)

=100g/mol

2Fe = 2×26

= 52

Therefore 100g of Fe2O3 gave 52g

749g of Fe2O3 will give

749×52/100

= 389.48g of Fe

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Answer:  


AB is an ionic compound. The electronegativity difference between A and B is greater.  


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6 0
3 years ago
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Need help !!!!! ASAP
Ksivusya [100]
<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of CO_{2}

n=0.120mol

<h2>Why?</h2>

We are asked to calculate the number of moles of the given gas, also, we  are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

R=62.363\frac{mmHg.L}{mol.K}

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°) + 273K

So, we are given the following information:

Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K

Now, isolating the number of moles, and substituting the given information, we have:

PV=nRT

n=\frac{PV}{RT}

n=\frac{PV}{RT}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole

Hence, we have that there were produced 0.120 moles of CO_{2}

n=0.120mol

Have a nice day!

7 0
3 years ago
Hich sentence most accurately describes electrically charged objects?
Ket [755]

Answer:

They attract or repel other charged objects without touching them.

Explanation:

My chemistry teacher always says like repels like opposite attracts.

4 0
3 years ago
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A researcher dilutes 30.0 ml of ethanol to 300.0 ml with distilled water. what is the percentage concentration by volume of the
Len [333]

Answer: 9.09 %

Explanation:

To calculate the  percentage concentration by volume, we use the formula:

\text{Volume percent of solution}=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100

Volume of ethanol (solute) = 30 ml

Volume of water (solvent) = 300 ml

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Putting values in above equation, we get:

\text{Volume percent of solution}=\frac{30}{30+300}\times 100=9.09\%

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3 years ago
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7.0 mol Mn reacts with 5.0 mol
Elenna [48]

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

<h3>What is a limiting reagent?</h3><h3 />

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

Learn more about stoichiometric law, here:

brainly.com/question/14465605

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2 years ago
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