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zysi [14]
3 years ago
7

What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the

horizontal?.
Physics
1 answer:
Olegator [25]3 years ago
3 0

The acceleration of the wagon along the ground is 3.6 m/s².

To solve the problem above, we need to use the formula of acceleration as related to force and mass.

Acceleration: This can be defined as the rate of change of velocity.

⇒ Formula:

  • Fcos∅ = ma................. Equation 1

⇒ Where:

  • F = Force
  • ∅ = angle above the horizontal
  • m = mass of the wagon
  • a = acceleration of the wagon

⇒ make a the subject of equation 1

  • a = Fcos∅/m..................... Equation 2

From the question,

⇒ Given:

  • F = 44 N
  • ∅ = 35°
  • m = 10 kg

⇒ Substitute these values into equation 2

  • a = 44(cos35°)/10
  • a = 44(0.8191)/10
  • a = 3.6 m/s²

Hence, The acceleration of the wagon along the ground is 3.6 m/s²

Learn more about acceleration here: brainly.com/question/9408577

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To answer this question, we should know the formula for the terminal velocity. The formula is written below:

v = √(2mg/ρAC)
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Let's determine the mass, m, to be density*volume.
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