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JulijaS [17]
3 years ago
13

A 60.0 kg astronaut is on a space walk away from the shuttle when her tether line breaks! She is able to throw her 10.0 kg oxyge

n tank away from the shuttle with a velocity of 12.0 m/s to propel herself back to the shuttle. Assuming that she starts from rest (relative to the shuttle), determine the maximum distance she can be from the craft when the line breaks and still return with 60.0 s ( the amount of time she can hold her breath).
Physics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

120 m

Explanation:

m_1 = Mass of Astronaut

m_1 = Mass of tank

v_1 = Velocity of Astronaut

v_2 = Velocity of tank

From conservation of linear momentum

m_1v_1=m_2v_2\\\Rightarrow v_1=\frac{m_2v_2}{m_1}\\\Rightarrow v_1=\frac{10\times 12}{60}\\\Rightarrow v_1=2\ m/s

Distance = Speed × Time

Distance=2\times 60=120\ m

So, the maximum distance she can travel is 120 m

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Explanation:

Given

Speed of marble at Bottom v=4.22 m/s

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As Energy is conserved therefore Energy at top is equal to energy at bottom

E_T=E_B

\frac{mv^2}{2}+mgh=\frac{mv_0^2}{2}  ,where v_0 is the velocity at bottom

\frac{v^2}{2}+gh=\frac{v_0^2}{2}

v_0^2=v^2+2gh

v^2=v_0^2-2gh

v=\sqrt{v_0^2-2gh}

v=\sqrt{4.22^2-2\times 9.8\times 0.286}

v=\sqrt{17.8084-5.6056}

v=3.49 m/s

                       

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In this case radius of circular motion = 0.19 meter

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Given: The mass of stone (m) = 0.5 kg

Raised from heights (h₁) = 1.0 m to (h₂) = 2.0 m

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Formula: The potential energy (P) = mgh

where, all alphabets are in their usual meanings.

Now, we shall calculate the change in potential energy of the stone

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