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JulijaS [17]
3 years ago
13

A 60.0 kg astronaut is on a space walk away from the shuttle when her tether line breaks! She is able to throw her 10.0 kg oxyge

n tank away from the shuttle with a velocity of 12.0 m/s to propel herself back to the shuttle. Assuming that she starts from rest (relative to the shuttle), determine the maximum distance she can be from the craft when the line breaks and still return with 60.0 s ( the amount of time she can hold her breath).
Physics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

120 m

Explanation:

m_1 = Mass of Astronaut

m_1 = Mass of tank

v_1 = Velocity of Astronaut

v_2 = Velocity of tank

From conservation of linear momentum

m_1v_1=m_2v_2\\\Rightarrow v_1=\frac{m_2v_2}{m_1}\\\Rightarrow v_1=\frac{10\times 12}{60}\\\Rightarrow v_1=2\ m/s

Distance = Speed × Time

Distance=2\times 60=120\ m

So, the maximum distance she can travel is 120 m

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Two point charges each carrying a charge of + 4.5 E - 6 C are located 4.5 meters away from each other. How strong is the electro
BARSIC [14]

Answer:

0.009 N, repulsive

Explanation:

The electrostatic force between two electric charges is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

In this problem, we have

q_1 =q_2 = +4.5\cdot 10^{-6}C are the two charges

r = 4.5 m is their separation

Substituting into the equation, we find

F=(9\cdot 10^9 Nm^2 C^{-2})\frac{(+4.5\cdot 10^{-6} C)(4.5\cdot 10^{-6} C)}{(4.5 m)^2}=0.009 N

Moreover, the force is repulsive. In fact, the following rules apply:

- When two charges have same sign, they repel each other

- When two charges have opposite signs, they attract each other

7 0
3 years ago
1. An electron travels 4.82 meters in 0.00360 seconds. What is its average speed?
vredina [299]

Answer:

speed =distance /time

speed =4.82/0.00360

speed =1338.8m/s

6 0
3 years ago
Which statement is true about the part of the electromagnetic spectrum that human eyes can detect?
LUCKY_DIMON [66]
Your answer is B. The human eye can only detect color and Tv waves
7 0
3 years ago
Read 2 more answers
A 4.4 nC charge exerts a repulsive force of 36 mN on a second charge which is located
zhenek [66]

The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.

They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.

The given data in the problem is;

q₁  is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C

F is the repulsive force = 36 mN =36 ×10⁶ N

d is the distance = 0.70 m

The Coulomb force is found as;

\rm F = \frac{Kq_1q_2}{r^2}\\\\\ \rm 36\times 10^6 = \frac{9 \times 10^9 }{(0.7)^2} \times 4.4 \times 10^{-9} \times q_2\\\\\ q_2 = 8.6241  \times 10^{-19 } \ C

Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.

To learn more about Coulomb's law, refer to the link;

brainly.com/question/1616890

#SPJ2

6 0
2 years ago
A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav
uysha [10]
In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0
3 years ago
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