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LekaFEV [45]
3 years ago
15

Which describes an inertial frame of reference?

Physics
2 answers:
nadezda [96]3 years ago
7 0

Newton's first law is valid within the frame describes an inertial frame of reference.

Answer: Option A

<u>Explanation: </u>

A frame of reference is defined as the system in which the motion or state of any object is observed and stated with respect to the set of space and time, observer or any other object or environment, either moving or at rest.  

The two types of frame of references to be studied by us are the Inertial and non-inertial.  An inertial reference frame is defined in that a body is either at rest or moves with a constant speed or velocity if there is no external force exerted upon it i.e. the objects are either rest or move at a same velocity.

Since it’s quite clear through the definition that an inertial frame of reference obeys Newton’s first law of motion, we have the first option as the perfect answer.

dexar [7]3 years ago
5 0
No forces are exerted within the frame
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A 6 kg block is released from rest at the top of an incline, as shown above, and slides to the bottom. The incline is 1.97 m lon
viva [34]

The net force on the block acting perpendicular to the incline is

∑ <em>F</em> = <em>n</em> - <em>w</em> cos(29.4°) = 0

where <em>n</em> is the magnitude of the normal force and <em>w</em> = <em>m g</em> is the weight of the block.

The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.

Solve for <em>n</em> :

<em>n</em> = <em>m g</em> cos(29.4°)

<em>n</em> = (6 kg) (9.80 m/s²) cos(29.4°)

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3 years ago
If a circling object is released, centrifugal force will make it travel away from the center of its original path.
9966 [12]

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5 0
3 years ago
WILL GIVE BRAINLIEST!!!
kumpel [21]

Answer:

72.53 mi/hr

Explanation:

From the question given above, the following data were obtained:

Vertical distance i.e Height (h) = 8.26 m

Horizontal distance (s) = 42.1 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the car to get to the ground.

This can be obtained as follow:

Height (h) = 8.26 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

8.26 = ½ × 9.8 × t²

8.26 = 4.9 × t²

Divide both side by 4.9

t² = 8.26 / 4.9

Take the square root of both side by

t = √(8.26 / 4.9)

t = 1.3 s

Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:

Horizontal distance (s) = 42.1 m

Time (t) = 1.3 s

Horizontal velocity (u) =?

s = ut

42.1 = u × 1.3

Divide both side by 1.3

u = 42.1 / 1.3

u = 32.38 m/s

Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:

1 m/s = 2.24 mi/hr

Therefore,

32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s

32.38 m/s = 72.53 mi/hr

Thus, the car was moving at a speed of

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7 0
3 years ago
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Tom [10]

Answer:

B. +m

Explanation:

The magnification of an image is defined as the ratio between the size of the image and of the object:

m = \frac{y'}{y}

where we have

y' = size of the image

y = size of the object

There are two possible situations:

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Therefore, the correct option representing an upright image is

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3 years ago
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Art [367]

Answer:

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Explanation:

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Gauge pressure is given as:

P = h*d*g

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Where

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d = density

g = acceleration due to gravity

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Therefore, the height of the tank is:

h = 79979.185/(997 * 9.8)

h = 8.19m

3 0
3 years ago
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