A boat sails south with the help of a wind blowing in the direction S36°E with magnitude 300 lb. Find the work done by the wind
1 answer:
You might be interested in
Answer: 1.51 km
Explanation:
<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.
Or,
Where Q1 and Q2 are magnitude of two charges and r is distance between them:
<u>Given:</u>
Q1 = Charge near top of cloud = 48.8 C
Q2 = Charge near the bottom of cloud = -41.7 C
Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N
k = 8.99 x 109Nm^2/C^2
<u>So,</u>
Therefore, the separation between the two charges (r) = 1.51 km
Answer:s=0.68 m
Explanation:
Given
Inclination
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using
Final velocity v=0
s=0.68 m
Answer:
8. acceleration = = 1 unit .
9. acceleration = = -1 unit.
10. acceleration = = 0 units.
Explanation:
8. i) acceleration = velocity / time
ii) In this figure velocity = time
iii) therefore acceleration = = 1 unit .
9. i) acceleration = velocity / time
ii) In this figure 4 = m + 5, therefore m = -1
therefore velocity = (-0.5 time) + 5
iii) therefore acceleration = = -1 units.
10.) velocity is constant at 2
therefore acceleration = = 0 units