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Llana [10]
3 years ago
11

Select all that apply. Which of the following do not illustrate a complete circuit? A B C D

Physics
2 answers:
ipn [44]3 years ago
7 0
There is not enough information here.
denpristay [2]3 years ago
5 0
The answer is b .. row 2
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What remains the same in a compound regardless of the quantity?
makvit [3.9K]
The ratio btw number of atoms.
example: water H2O is the compound. No matter how much water you take (a liter, 10 cubic meters... whole swimming pool), the proportion btw hydrogen atoms and oxygen would be always 2 to 1.
8 0
3 years ago
how fast in revolutions per minute must a centrifuge rotate in order to subject the contents of a test tube (30cm) from the axis
trapecia [35]

Answer:

ω=6684.51 rpm

Explanation:

r= 30cm= 0.3m

a= 15000gs (convert to m/s^{2}

1g = 9.8 m/s^{2}

a= 15000 *9.8 = 147000 m/s^{2}

a=\frac{v^{2} }{r}

147000 = \frac{v^{2} }{0.3}

147000*0.3 = v^{2}

44100 = v^{2}

√44100 = v

210m/s  = v

v=210m/s (linear velocity)

we will convert this to angular velocity

ω=\frac{v}{r}  

ω= 210/0.3

ω= 700 rads^{-1}

we will convert this to rev per minute

1rad per second = 9.5493 rev per minute

ω= 700*9.5493

ω=6684.51 rpm

4 0
3 years ago
Please help for 21! will mark brainliest
Katyanochek1 [597]

The answer for this question is D

5 0
3 years ago
9. Calculate the distance (in km) that Charlie runs if he maintains the average
Karo-lina-s [1.5K]

<u>Correct Question:</u>

Calculate the distance (in km) charlie runs if he maintains an average speed of 8 km/hr for 1 hour

<u>Answer:</u>

The total distance covered by Charlie is 8 km in 1 hour.

<u>Explanation:</u>

The average velocity as given in the question is,

v = 8 km/hr

Total time taken,

$t=1 hour

As we know the formula to evaluate the total distance d when the average velocity and time is given;

v=\frac{d}{t}

d=v \times t

d=8 \times 1

d=8 k m

Hence, the total distance covered by Charlie in 1 hour will be 8 km.

5 0
3 years ago
discharge occurs when oppositely charged objects get close enough for the air between them to become electrically charged.
Wittaler [7]

Answer:

It does both. Once they get close enough the air does start to get charged, but then they eventually discharge when they touch.

Explanation:

4 0
3 years ago
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