Answer:
I'll try to help which grade are you?
Answer:
-3 m
Explanation:
Displacement is the final position minus the initial position.
Δx = x − x₀
Δx = -3 m − 0 m
Δx = -3 m
We have that for the Question it can be said that The maximum height reached by the first <em>object</em> will be 100 times that of the other.
From the question we are told
One object is thrown vertically upward with an initial velocity of 100 m/s and another object with an initial velocity of 10 m/s. The maximum height reached by the first object will be
that of the other.
a. 10,000 times
b. none of these
<em>c. </em><em>1000 times</em>
d. 100 times
<em>e.</em><em> 10 times</em>
Generally the equation for the velocity is mathematically given as


Therefore
The maximum height reached by the first <em>object</em> will be 100 times that of the other.

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Answer:
By the information given, I am not sure how the event has played out. However, using common knowledge, I can give a scenario of how it may play out.
When removing the first block (the foundation), gravity will pull the other blocks down, as the strength of gravity exceeds that of the strength of air holding it up. This means that all the blocks on top would fall.
By definition of Newton's 1st - 3rd laws, the blocks would not move unless a force is given to it (i.e., removing the bottom block, which causes gravity). Gravity would pull the other blocks downwards. This would lead to the falling of the stack of blocks.
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Answer:
Ep = 0.6095 [J]
Explanation:
As defined in the problem statement, potential energy is defined as the product of mass by gravity by height. But first we must convert all the values given to measures of the international system (SI)
g = gravity = 10 [m/s^2]
h = elevation = 40 [ft] = 12.19 [m]
m = mass = 5 [g] = 0.005 [kg]
Ep = potential energy [J]
Ep = 0.005*10*12.19 = 0.6095 [J]