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Brut [27]
3 years ago
10

Elizabeth .........................................................................

Physics
2 answers:
Ksivusya [100]3 years ago
8 0

Answer:

What about it?

Explanation:

Umnica [9.8K]3 years ago
7 0

Answer:

who's elizabeth? haha

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How many atoms of oxygen are in the molecule: H2O2
suter [353]

Answer:

C their is 2

Explanation:

5 0
2 years ago
Read 2 more answers
How far will a 70N crate is move with 3500J of work
r-ruslan [8.4K]
Work = Force * distance
Force = 70 N
Work = 3500 J

3500 = 70d
d = 3500/70 = 50 m
6 0
3 years ago
Read 2 more answers
A sports car accelerates from rest for 5 seconds reaching a velocity of 23.0 m/s.
denis-greek [22]

Answer:

<h2>4.6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

<h3>a =  \frac{v - u}{t}  \\</h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

Since the body is from rest u = 0

From the question we have

a =  \frac{23 - 0}{5}  =  \frac{23}{5}  \\

We have the final answer as

<h3>4.6 m/s²</h3>

Hope this helps you

4 0
2 years ago
a truck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the horizontal and vertical com
Kamila [148]

Answer:

speed of truck (v) =  22 m/s ,

angle of hill (Θ) =15°

Find

Vertical component (Fv) = ?

Harizontal component (Fh) =?

               Vertical component (Fh) = V cosΘ

                                                        = 22. cos 15

                                                        = 21.25 m/s.

               Harizontal component (Fv) = V sinΘ

                                                            = 22. sin 15

                                                            = 5.69 m/s.

3 0
3 years ago
A city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be
Artyom0805 [142]

Explanation:

It is known that relation between force and acceleration is as follows.

                      F = m \times a

I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.

              F = m \times a      

                 = 1090 \times (\frac{21}{16})

                 = 1430.625 N

Also, it is known that

      sin(\theta) = \frac{\text{Force car can exert}}{\text{Force gravity pulls car}}

      sin(\theta) = \frac{1430.625 N}{(1090 \times 9.8) N}

        \theta = 7.70 degrees

Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.

8 0
3 years ago
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