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Brut [27]
3 years ago
10

Elizabeth .........................................................................

Physics
2 answers:
Ksivusya [100]3 years ago
8 0

Answer:

What about it?

Explanation:

Umnica [9.8K]3 years ago
7 0

Answer:

who's elizabeth? haha

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A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 385 kV. The secondary of
enot [183]

Answer:

a) In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new output is 86% of the old output

c) The losses in the new line are 74% the losses in the old line.

Explanation:

a) To relate the turns of primary and secondary to the ratio of voltage we have this expression:

\frac{n_1}{n_2}=\frac{V_1}{V_2}

In the old transformer the ratio of voltages was:

\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{385} =0.03117\\\\n_2=n_1/0.03117=32.1n_1

In the new transformer the ratio of voltages is:

\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{500} =0.024\\\\n_2=n_1/0.24=41.7n_1

In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new current ratio is

\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{500}= 0.024\\\\I_2=0.024I_1

If the old current output was 425 kV, the ratio of current was:

\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{425}= 0.028\\\\I_2=0.028I_1

Then, the ratio of the new output over the old output is:

\frac{I_{2new}}{I_{2old}} =\frac{0.024\cdot I_1}{0.028\cdot I_1}= 0.86

The new output is 86% of the old output (smaller output currents lower the losses on the transmission line).

c) The power loss is expressed as:

P_L=I^2\cdot R

Then, the ratio of losses is (R is constant for both power losses):

\frac{P_n}{P_o} =\frac{I_n^2R}{I_o^2R} =(\frac{I_n}{I_o} )^2=0.86^2=0.74

The losses in the new line are 74% the losses in the old line.

7 0
3 years ago
An object starts at 4m/s and accelerates to 6m/s in 10 seconds. Find its displacement.
Natalka [10]

Answer:

Explanation:

The 2 equations we need here are, first:

a=\frac{v_f-v_0}{t} and then once we solve for the acceleration here:

v^2=v_0^2+2aΔx

Solving for acceleration:

a=\frac{6-4}{10}=\frac{1}{5}\frac{m}{s^2} and now we will use that in the other equation:

6^2=4^2+2(\frac{1}{5})Δx and

36 = 16 + \frac{2}{5}Δx and

20 = \frac{2}{5}Δx and

\frac{5}{2}(20)= Δx so

Δx = 50 m

6 0
3 years ago
I need help on the question in the photo
kiruha [24]
The ironwood will because it it more heavy and the others are not
The higher the amount is the more possible it is to sink
Hope this helped
7 0
3 years ago
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Which of these represents three molecules of carbon dioxide? 3CO2 3C3O2 C3O6 3C2O
seraphim [82]
............ Answer is 3C02
5 0
3 years ago
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If you're not satisfied with your fitness evaluation score, there's really little you can do about it.
BARSIC [14]

Answer:

False

Explanation:

3 0
3 years ago
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