Work = Force * distance
Force = 70 N
Work = 3500 J
3500 = 70d
d = 3500/70 = 50 m
Answer:
<h2>4.6 m/s²</h2>
Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula
<h3>

</h3>
where
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
Since the body is from rest u = 0
From the question we have

We have the final answer as
<h3>4.6 m/s²</h3>
Hope this helps you
Answer:
speed of truck (v) = 22 m/s ,
angle of hill (Θ) =15°
Find
Vertical component (Fv) = ?
Harizontal component (Fh) =?
Vertical component (Fh) = V cosΘ
= 22. cos 15
= 21.25 m/s.
Harizontal component (Fv) = V sinΘ
= 22. sin 15
= 5.69 m/s.
Explanation:
It is known that relation between force and acceleration is as follows.
F =
I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.
F =
=
= 1430.625 N
Also, it is known that
= 7.70 degrees
Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.