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Zinaida [17]
3 years ago
14

How do I solve 16th qns.?answer asap

Physics
1 answer:
arsen [322]3 years ago
4 0

It really doesn't matter whether the two masses are joined by a light string, a light reinforced concrete and steel frame, a light coating of strong glue, or a layer of scotch tape that's one atom thick.  They look like a single mass of 10 kg.

<u>Part a). </u>Force = (mass) x (acceleration)

The acceleration of 10 kg of mass pulled with 100N of force is

100 N = (10 kg) x (acceleration)

Divide each side by (10 kg):  

Acceleration = (100 N) / (10 kg)

<em>Acceleration = 10 m/s²</em>

<u>Part b).</u>  Now look at just the rear 16 kg.  It stays hooked onto the front 4 kg, and everything moves together.  So both pieces must have the same distance, velocity, acceleration etc.  We know that the acceleration is 10 m/s² .

Force = (mass) x (acceleration)

Force on the rear 16 kg = (16 kg) x (10 m/s²)

<em>Force = 160 Newtons</em>

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A simple electric motor consists of a 220-turn coil, 4.4 cm in diameter, mounted between the poles of a magnet that produces a 9
Verdich [7]

Answer:

M = 5.01\ A.m^2          

Explanation:

It is given that,

Number of turns in the coil, N = 220

Diameter of the coil, d = 4.4 cm

Radius of the coil, r = 2.2 cm = 0.022 m

Magnetic field produced by the poles of magnet, B=96\ mT=96\times 10^{-3}\ T

Current flowing in the coil, I = 15 A

Let M is the coil's magnetic dipole moment. Its formula is given by :

M=N\times I\times A

M=220\times 15\times \pi (0.022)^2

M = 5.01\ A.m^2

So, the coil's magnetic dipole moment is 5.01\ A.m^2. Hence, this is the required solution.

4 0
3 years ago
Kirchhoff's loop rule for circuit analysis is an expression of which of the following? Conservation of charge Conservation of en
Irina18 [472]

Kirchhoff's circuit laws are two equalities that deal with the current and potential difference (commonly known as voltage) in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff. This generalized the work of Georg Ohm and preceded the work of Maxwell.

6 0
3 years ago
In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the
GaryK [48]

We will determine the wavelength through the relationship given by the distance between slits, this relationship is given under the function

y = \frac{m\lambda}{d}

Here,

m = Number of order bright fringe

\lambda = Wavelength

d = Distance between slits

Both distance are the same, then

y_1 = y_2

\frac{m_1\lambda_1 r}{d} = \frac{m_2\lambda_2 r}{d}

\frac{m_1\lambda_1}{m_2\lambda_2} =1

 Rearranging to find the second wavelength

m_1 \lambda_1 = m_2 \lambda _2

\lambda_2 = \frac{m_1\lambda_1}{m_2}

\lambda_2 = \frac{7(629)}{8}

\lambda_2 = 550.3nm

Therefore the wavelength of the light coming from the second monochromatic light source is 550.3nm

7 0
3 years ago
A single strain gage has a nominal resistance of 120 ohm. For a quarter bridge with 120 ohm fixed resistors, strain gauge factor
natita [175]

Answer:

Output voltage is 1.507 mV

Solution:

As per the question:

Nominal resistance, R = 120\Omega

Fixed resistance, R = 120\Omega

Gauge Factor, G.F = 2.01

Supply Voltage, V_{s} = 3\ V

Strain, \epsilon = 1000\times 10^{-6}\ strain

Now,

To calculate the output voltage, V_{o}:

WE know that strain is given by:

\epsilon = \frac{(R + R')^{2}V_{o}}{RR'V_{s}\times G.F}

Thus

V_{o} = \frac{RR'V_{s}\epsilon \times G.F}{(R + R')^{2}}

Now, substituting the suitable values in the above eqn:

V_{o} = \frac{120\times 120\times 3\times 1000\times 10^{-6}\times 2.01}{(120 + 120)^{2}}

V_{o} = 1.507\ mV

6 0
4 years ago
Free tingsssssssssss
il63 [147K]

Explanation:

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5 0
2 years ago
Read 2 more answers
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