Solve for x. a²x+(a-8)=(a+8)x
2 answers:
Solve for x.
a2x+a−8=(a+8)(x)
Add -8x to both sides.
a^2x+a−8+−8x=ax+8x+−8x
a^2x+a−8x−8=ax
Add -ax to both sides.
a^2x+a−8x−8+−ax=ax+−ax
a^2x−ax+a−8x−8=0
Add 8 to both sides.
a^2x−ax+a−8x−8+8=0+8
a^2x−ax+a−8x=8
Add -a to both sides.
a^2x−ax+a−8x+−a=8+−a
a^2x−ax−8x=−a+8
Factor out variable x.
x(a^2−a−8)=−a+8
Divide both sides by a^2-a-8.
x(a^2−a−8) / a^2−a−8 = −a+8 / a^2−a−8
a2x+a−8=(a+8)(x)
Add -8x to both sides.
a^2x+a−8+−8x=ax+8x+−8x
a^2x+a−8x−8=ax
Add -ax to both sides.
a^2x+a−8x−8+−ax=ax+−ax
a^2x−ax+a−8x−8=0
Add 8 to both sides.
a^2x−ax+a−8x−8+8=0+8
a^2x−ax+a−8x=8
Add -a to both sides.
a^2x−ax+a−8x+−a=8+−a
a^2x−ax−8x=−a+8
Factor out variable x.
x(a^2−a−8)=−a+8
Divide both sides by a^2-a-8.
x(a^2−a−8) / a^2−a−8 = −a+8 / a^2−a−8
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If the midpoint of segment lm where j(5, -1) and m(0, 6), then the coordinates of end point l is (10,-8)..
Midpoint:
Midpoint of a line segment is the point that is halfway between the endpoints of the line segment.
The formula for the midpoint is,
where,
= coordinates of the midpoint
(x₁, y₁) = coordinates of the first point
(x₂, y₂) = coordinates of the second point
Given,
Midpoint = j = (5,-1)
Second point = m = (0,6)
Now, we have to find the first midpoint l.
Let (x,y) be the coordinates of l.
Then apply the values on the formula,
Then we get,
Compare the values in order to find the coordinates,
=> 5 = (x + 0) / 2
=> 5 x 2 = x + 0
=> 10 = x
Similarly,
=> -1 = (y + 6) / 2
=> -1 x 2 = y + 6
=> -2 = y + 6
=> -2 - 6 = y
=> y = -8
Therefore, the coordinates of l is (10,-8).
To know more about Midpoint here.
#SPJ4
Answer:
Option: c is correct.
Step-by-step explanation:
We are given that paco needs at least 3/8 yard of twine to build a model ship.
that is we require twine of amount greater than 3/8 yards.
<em>now we need to check among the given options which quantity is greater than 3/8 yards.</em>
a)
3/10 yard.
As we know that for two rational numbers with the same numerator but with different denominator the number whose denominator is smaller is a greater quantity.
Hence 3/10 < 3/8
Hence option a is incorrect.
b)
1/4 yard
As to compare to rational numbers we have to either make the numerator equal or their denominator equal. Hence here we multiply and divide 1/4 by 2 to get 8 in the denominator.
as 2/8 < 3/8
since the denominator is same and the number with the same denominator but with different numerator are compared as whose numerator is greater is a greater quantity.
Hence option b is incorrect.
c)
3/4 yard
Clearly both the numbers have the same numerator but different denominator and we know that for two rational numbers with the same numerator but with different denominator the number whose denominator is smaller is a greater quantity.
Hence 3/8 < 3/4
Hence, option c is correct.
d)
1/8 yard
clearly both the numbers have the same denominator and we know that for two rational numbers withe same denominator but with different numerator the number whose numerator is smaller is a smaller quantity.
Hence, 1/8 < 3/8
Hence, option d is incorrect.