A refrigerator recieves 240 V of electricity. If it use 32 A of current, what is the resistance of the refrigerator?
1 answer:
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Answer:
Electric potential, E = 2100 volts
Explanation:
Given that,
Electric field, E = 3000 N/C
We need to find the electric potential at a point 0.7 m above the surface, d = 0.7 m
The electric potential is given by :
V = 2100 volts
So, the electric potential at a point 0.7 m above the surface is 2100 volts. Hence, this is the required solution.
Answer:
Energy= 46.08KJ
Explanation:
Given that the power needed to light each bulb is 32W
We know that Power =
The energy needed to light one bulb=
Given time = 1minute = 60 seconds
Energy = =1920J
Therefore energy needed to light one bulb is 1920J
The energy needed to light 24 bulbs = =46080J=46.08KJ