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3 years ago

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You measure the absorbency of a 0.5 ml solution and you find that it is 1.2. you then dilute this solution by adding 0.5 ml of p

ure water, making the final volume 1.0. what will be the absorbency of the diluted solution?

1 answer:

ivann1987 [24]3 years ago

8 0

The absorbency of the diluted solution would be 0.6

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Identify each section of the periodic table.<br><br> metals<br> nonmetals<br> metalloids

Len [333]

Answer:

i added this table for some help

Explanation:

here are some examples

<u>metals:</u>They are hard and shiny, strong, and easy to shape. They are used for many industrial purposes. This group includes iron, gold, silver, chromium, nickel, and copper, some of which are also noble metals.

<u>non-metals:</u>a chemical element (as boron, carbon, or nitrogen) that lacks the characteristics of a metal and that is able to form anions, acidic oxides, acids, and stable compounds with hydrogen.

<u>metalloids:</u>Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor. Metalloids have mixed properties which are difficult to characterize.

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3 years ago

Read 2 more answers

How many molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium? 4na o2 -> 2na2o

Leona [35]

Molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium will be 7.04 × 10 ²⁴ molecules.

Sodium oxide is Na₂O which is formed due to the reaction of sodium and oxygen.

Given,

Balanced chemical equation is :

4 Na(s) + O₂ (g) → 2Na₂O (s)

Now, the Mole ratio of O₂ and Na₂O is 1 mol O₂: 2 mol Na₂O

Molar mass O₂ = 32.00 g/mol

Now, let's find out the Number of moles of O₂ present in 187 grams of oxygen,

Number of moles of O₂ = Given mass in grams / molar mass of O₂

Number of moles of O₂ = 187 g / 32.00 g/mol

Number of moles of O₂ = 5.844 mol

Since, we know the Proportion is 1 mol O₂ : 2 mol Na₂O

Now, Number of moles of Na₂O required is,

2 mol Na₂O / 1 mol O₂ = 5.844 mol O₂ / x

x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂)

x = 11.688 mol Na₂O

To calculate the Number of molecules of sodium oxide,

Number of molecules = Number of moles × Avogadro's number

Number of molecules = 11.688 mol × 6.022 × 10²³ molecules/mol =

Number of molecules = 7.04 × 10 ²⁴ molecules

Hence, the Number of molecules of sodium oxide required is 7.04 × 10²⁴ molecules.

Learn more about Sodium oxide here,

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2 years ago

What is the percent composition of NaHCO3?

zhuklara [117]

Answer:

Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

a) Na = 22.99 g/mol

b) H = 1.01 g/mol

c) C = 12.01 g/mol

d) O₃ = 16.0 × 3 = 48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

Na = 22.99 g/mol

H = 1.01 g/mol

C = 12.01 g/mol

O₃ = 48 g/mol

----------------------------------

Total 84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

= 22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 27.36 %

For H:

= 1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 1.20 %

For C:

= 12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 14.29 % ≈ 14.30 %

For O:

= 48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 57.13 % ≈ 57.14 %

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3 years ago

Will mark brainliest

MArishka [77]

Answer:

D. water

<h2><em>H</em><em>ope it will help you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2>

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3 years ago

A Wisconsin farmer taps a maple tree and collects 200 liters of sap. He determines the sucrose (C12H2011) concentration to be 0.

Minchanka [31]

Answer:

6.0 L

Explanation:

Use the dilution equation M1V1 = M2V2

M1 = 0.075 M

V1 = 200 L

M2 = 2.5 M

V2 = ?

Solve for V2 --> V2 = M1V1/M2

V2 = (0.075 M)(200 L) / (2.5 M) = 6.0 L

4 0

3 years ago