To be able to classify which species is which
It is 10^4 times the intensity at 0 db
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Below is the answers:
Fullback running
<span>Mo = mass * velocity </span>
<span>Mo = 95kg * 8.2 m/s =779 kg*m/s (a </span>
<span>He got stopped Change in Mo = 779 kg*m/s (b </span>
<span>Both stopped ===> Tackle's mo = - Halfback's Mo = - 779 kg*m/s (c & d </span>
<span>- 779 = 128 * v </span>
<span>v= - 6.09 m/s (e</span>
Answer:
10.19 m
Explanation:
Water will rise to equalize the pressure inside and outside the tube.
The equation of pressure is given by
![p=\rho gh](https://tex.z-dn.net/?f=p%3D%5Crho%20gh)
Where,
p = Pressure of air = 10⁵ N/m²
ρ = Density of water = 10³ kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Height the water will rise
![h=\frac{p}{gh}\\\Rightarrow h=\frac{10^5}{9.81\times 10^3}\\\Rightarrow h=10.19\ m](https://tex.z-dn.net/?f=h%3D%5Cfrac%7Bp%7D%7Bgh%7D%5C%5C%5CRightarrow%20h%3D%5Cfrac%7B10%5E5%7D%7B9.81%5Ctimes%2010%5E3%7D%5C%5C%5CRightarrow%20h%3D10.19%5C%20m)
∴ The water will rise by 10.19 m.
Answer:
The field gets weaker
Explanation:
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