To find the work done on the particle, the following is the
solution:
Dw = F dx
W = integral over the path ( F(x) dx)
W = integral from 0 to 1 (e^(-x/5 + 5) dx)
W = -5e^(-x/5 + 5) from 0 to 1
W = 135 J
The work done is 135 J.
Answer:
Calcium sulphide
Explanation:
If we look at the compound, we will discover that it is an ionic compound. The compound is comprised of Ca^2+ and S^2-.
The cation Ca^2+ is the calcium ion while the anion S^2- is the sulphide ion hence the compound is rightly named calcium sulphide.
Increasing the masses of the objects and decreasing the distance between the objects
Answer:
Explanation:
Here the rope is 10m long and making an angle of θ with the direction of canal or direction of flow of water in the canal .
sinθ = 2 / 10 = .2
θ = 11.5⁰
a )
Component of 500 N along the line perpendicular to the canal
= 500 sinθ
= 500 sin 11.5
= 100 N
b )
component of 500 N along the canal
= 500 cos 11.5
= 490 N approx .