Question

You have 4.9 g of an unknown substance. To identify the substance, you decide to measure its specific heat and find that it requires 668.85 J of heat to increase the temperature of your sample by 39 K. What might this substance be?

Answer 1

The unknown substance can be lithium, which has a specific heat capacity of approximately $3.5 J/gK$.

Explanation:

When heat energy is supplied to a certain substance, the temperature of the substance increases according to the equation:

$Q=mC_s \Delta T$

where

Q is the amount of energy supplied

m is the mass of the sample

$C_s$ is the specific heat capacity of the substance

$\Delta T$ is the change in temperature

In this problem, we have

m = 4.9 g is the mass

Q = 668.85 J is the specific heat capacity

$\Delta T = 39 K$ is the change in temperature

Solving for $C_s$, we find the specific heat capacity of the substance:

$C_s = \frac{Q}{m\Delta T}=\frac{668.85}{(4.9)(39)}=3.5 J/gK$

Looking at tables of specific heat capacity, we can see that the unknown substance can be lithium, which has a specific heat capacity of approximately $3.5 J/gK$.

Learn more about specific heat capacity:

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