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Elena-2011 [213]
4 years ago
7

Fill in the coefficients that will balance the following reaction:

Chemistry
2 answers:
Anon25 [30]4 years ago
6 0
2NaCl + CaS → Na₂S + CaCl₂
MariettaO [177]4 years ago
3 0
Its 4NaCl + 2CaS -> 2Na2S + 2CaCl2
and since there are 4 and 2, you can divide with 2 so
2NaCl+CaS->Na2S+CaCl2
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8 0
3 years ago
Identify and name the functional<br> present in (i) C₂ H₂ (ii). CH₃ CH₂OH.
Minchanka [31]

Answer:

I)Acetylene

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6 0
3 years ago
Referring only to the periodic table, tell:
denpristay [2]

a) Both fluorine and chlorine are in the same group in periodic table.

b) They differ in their atomic radius and electronegativity.

c) Because they have the similar number of electrons in their outer shell.

Explanation:

a) Electronic configuration of chlorine and fluorine are similar because these two elements belong to the same group number 17 of the periodic table as they have the same number of electrons in their outer or valence shell. These are called as halogens and are highly reactant.

F - 1s2,2s2,2p5    (9)

Cl- 1s2,2s2,2p6,3s2,3p5  (17)

b. The atomic radius of chlorine and fluorine are different because fluorine is on top of chlorine in the group. We know as we go down in a group in the periodic table the atomic radius increases though they have the same number of electrons in their outer shell electronegativity decreases. Fluorine is the most electronegative element of the periodic table.

c) Iodine and bromine are also the members of group 17, although their atomic numbers are different they have same valence electrons as chlorine and fluorine.

Iodine electronic configuration: 1s2,2s2,2p6,3s2.........4d10,5s2,5p5.

Bromine electronic configuration: 1s2,2s2,2p6,3s2,........3d10,4s2,4p5

Chlorine electronic configuration: 1s2,2s2,2p6,3s2,3p5

We can observe the outer shell having same number of electrons.

8 0
4 years ago
1. Mass is measured with and instrument called a _____
Brilliant_brown [7]
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4 0
4 years ago
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SIZIF [17.4K]
The correct answer is A. molecular formula = 2 x empirical formula

The given compound C2H10N2 is the molecular formula because the ratios of the elements are not reduced into lowest terms (empirical formula). To get the empirical formula, the ratios must be reduced to the smallest possible integral ratio which gives CH5N. As a result, the ratio between both formulas is 2.
3 0
3 years ago
Read 2 more answers
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