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Romashka-Z-Leto [24]

3 years ago

15

Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d

escribe as which of the following?
A. revolutionary
B. rotational
C. periodical
D. elliptical

1 answer:

n200080 [17]3 years ago

5 0

The scientists describe them as D. Elliptical

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The skater is has a mass of 75 kg. Find the total Potential energy of the skater at the top of the ramp at 6 m.

AlekseyPX

P= mgh
= 75*9,81*6= 4415 j

4 0

3 years ago

A flywheel with radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.400 rad/s2.For a po

oksian1 [2.3K]

Answer:

$0.12\ m/s^2$

Explanation:

Given that,

The radius of a flywheel, r = 0.3 m

Angular acceleration of a flywheel, $\alpha =0.4\ rad/s^2$

We need to find the magnitude of the tangential acceleration after 2.00 s of acceleration.

The relation between the tangential and angular acceleration is given by :

$a_t=r\alpha \\\\a_t=0.3\times 0.4\\\\a_t=0.12\ m/s^2$

So, the required magnitude of tangential acceleration is $0.12\ m/s^2$ .

6 0

3 years ago

What does the geology of the two continents indicate about past events in Earth history?

Nikolay [14]

Answer:

Explanation:

Rocks tell us a great deal about the Earth's history. Igneous rocks tell of past volcanic episodes and can also be used to age-date certain periods in the past. Sedimentary rocks often record past depositional environments (e.g deep ocean, shallow shelf, fluvial) and usually contain the most fossils from past ages.

6 0

3 years ago

Students perform a set of experiments by placing a block of mass m against a spring, compressing the spring a distance x along a

Verizon [17]

Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

The statement that indicates how the relationship between <em>v</em> and <em>x</em> changes is;<u> As </u><u><em>x</em></u><u> increases, </u><u><em>v</em></u><u> increases, but the relationship is no longer linear and the values of </u><u><em>v</em></u><u> will be less for the same value of </u><u><em>x</em></u><u>.</u>

Reasons:

The energy given to the block by the spring = $\mathbf{0.5 \cdot k \cdot x^2}$

According to the principle of conservation of energy, we have;

On a flat plane, energy given to the block = $0.5 \cdot k \cdot x^2$ = kinetic energy of

block = $0.5 \cdot m \cdot v^2$

Therefore;

0.5·k·x² = 0.5·m·v²

Which gives;

x² ∝ v²

x ∝ v

On a plane inclined at an angle θ, we have;

The energy of the spring = $\mathbf{0.5 \cdot k \cdot x^2}$

The force of the weight of the block on the string, $F = m \cdot g \cdot sin(\theta)$

The energy given to the block = $0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta)$ = The kinetic energy of block as it leaves the spring = $\mathbf{0.5 \cdot m \cdot v^2}$

Which gives;

$0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta) = 0.5 \cdot m \cdot v^2$

Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

Where;

a, b, and <em>c</em> are constants

The graph of the equation a·x² + c·v² = b is an ellipse

Therefore;

As <em>x</em> increases, <em>v</em> increases, however, the value of <em>v</em> obtained will be lesser than the same value of <em>x</em> as when the block is on a flat plane.

<em>Please find attached a drawing related to the question obtained from a similar question online</em>

<em>The possible question options are;</em>

<em>As x increases, v increases, but the relationship is no longer linear and the values of v will be less for the same value of x</em>

<em>The relationship is no longer linear and v will be more for the same value of x</em>

<em>The relationship is still linear, with lesser value of v</em>

<em>The relationship is still linear, with higher value of v</em>

<em>The relationship is still linear, but vary inversely, such that as x increases, v decreases</em>

<em />

Learn more here:

brainly.com/question/9134528

6 0

2 years ago

The length of second, s pendulum at a place where gravitational acceleration ]g] is 9.8 m/s

amm1812

O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)

6 0

3 years ago