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ddd [48]
3 years ago
7

How to calculate maximum height, when i know only V Pleeeaaassseee as fast as you can

Physics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer: was it this problem?

Explanation:

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What is the magnitude of the net force acting on a 2.0 x10^3 kilogram car?
Tatiana [17]
Answer:  
Acceleration= final velocity - initial velocity / time
 = (15 - 0)/ 5
 = 3 m/s^2
 Force = mass X acceleration
 = 2 X 10^3 X 3
 = 6 X 10^3 N
7 0
3 years ago
Ernie speed walks at the rate of 20m/s in 5 seconds. Calculate the distance he traveled
taurus [48]

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

7 0
3 years ago
This is the solid outermost layer of the Earth, including the crust and upper-mantle.
mr_godi [17]
Together the crust and upper mantle are called the lithosphere
7 0
4 years ago
Read 2 more answers
A coil of conducting wire carries a current of i(t) = 14.0 sin(1.15 ✕ 103t), where i is in amperes and t is in seconds. A second
Advocard [28]

Answer:

The peak emf in second coil is 1.876 V

Explanation:

Given :

Inductance L = 130 \times 10^{-6} H

The current I(t) = 14 \sin(1.15\times 10^{3} t)

We compare above equation with standard equation,

  I(t) = I_{o} \sin (\omega t + \phi)

From above equation we have,

  \omega = 10^{3} and \phi = 1.15

Find the inductive resistance,

  X_{L} = \omega L

  X_{L} = 10^{3}  \times 130  \times 10^{-6}

  X_{L} = 0.134

The peak emf in second coil is,

   V = I_{o} X_{L}

  V = 14 \times 0.134

  V = 1.876 V

Therefore, the peak emf in second coil is 1.876 V

8 0
4 years ago
A uniform horizontal beam of weight 481 N and length 3.32 m has two weights hanging from it. One weight of 381 N is located 0.87
Andre45 [30]

Answer:

1143 N at 1.59 m from the left end

Explanation:

For the system to produce equilibrium, the total force and moment must be 0. Since the total weight downward is

481 + 381 + 281 = 1143 N

Therefore the magnitude of the force acting upward to balance this system must be the same of 1143 N

That alone is not enough, we also need the position of the force for the total moment to be 0.

Let x be the length from the this upward force to the left side. And let the left point be the point of reference for moment arm:

481 * 3.32/2 + 381 * 0.8798 + 281*(3.32 - 0.8798) - 1143*x = 0

x = (481*1.66 + 381 * 0.8798 + 281*2.4402)/1143 = 1.59m

5 0
4 years ago
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