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vovikov84 [41]
3 years ago
6

Fill in the blank below: In a _______________ digestive system, digestion takes place outside of the cells in a series of tubes.

Food enters one opening and food remnants exit out of a different opening. Examples of organisms with this type of digestive system include you, dogs, horses, spiders and earthworms. A) Intracellular B) Sponge C) Incomplete D) Complete
Physics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer : Option D) Complete.

Explanation : In a complete digestive system, digestion takes place outside of the cells in a series of tubes. Food enters through one opening and food remnants exit out of a different opening. It has examples of humans, dogs, horses, spiders and earthworms. This system is complete because it does not occurs inside a cell nor it occurs in sponge kind-off organs and it is also not incomplete digestion as the waste products are removed from the other opening.

Therefore, the correct answer is option D) complete.

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A ball is thrown horizontally at 20 m/s from the top of a cliff 50 meters high. how far from the base of the cliff does the ball
Oksanka [162]
You need to divide the motion into its component: vertical and horizontal motion.

The time taken to fall vertically from the cliff is equal to the time taken to move horizontally.

Using the vertical component, which is an accelerated motion with an initial velocity equal to zero, we can solve for t:
h = 1/2 · g · t²

t = √(2·h / g)
  = √(2·50 / 9.8)
  = 3.2 s

Horizontally, it is a constant motion:
d = v · t
   = 20 · 3.2
   = 64 m

The ball will strike the ground at a distance of 64 meters from the cliff.
6 0
3 years ago
Black smokers are hot volcanic vents that emit smoke deep in the ocean floor. Many of them teem with exotic creatures, and some
erica [24]

If the density of water does not vary and the vents range in depth from about 1500 m to 3200 m below the surface, then the gauge pressure at a 2452-m deep vent is 224.268 atm.

Calculation:

Step-1:

It is given that the vents range in depth from about 1500 m to 3200 m below the surface. If we are assuming that the density of water does not vary. Then it is required to calculate the gauge pressure at a 2452-m deep vent.

The gauge pressure at a particular depth of ocean water is calculated as:

$$P=\rho g h$$

Here \rho is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.

Step-2:

Now we are substituting the values to calculate the pressure at the depth of 2452-m.

$$\\\begin{aligned}\\P&=\rho gh\\&=1030 (\text{ kg/m}^3)\times 9.8 (\text{ m/s}^2)\times 2452 \text{ m}\\&=24.75\times 10^6 \text{ Pa}\times\frac{1 \text{ atm}}{10.1325 \times10^4 \text{ Pa}}\\&=224.268 \text{ atm}\\\end{aligned}\\$$

Learn more about gauge pressure here,

brainly.com/question/14012416

#SPJ4

5 0
2 years ago
Intersystem crossing is:
Semenov [28]

An intersystem crossing (ISC) is a non-radiative process that involves the transition between two electronic states with different spin multiplicity. That is, when an electron is excited in a molecule in a basal singlet state (either by absorption or radiation) into a state of greater energy, an excited singlet or triplet state can be obtained.

Therefore, ISC is understood as an a non radio active transition between states with different spin multiplicity.

Correct answer is C:  a radiative transition between states with the same spin.

8 0
4 years ago
A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 nm and an index of 1.630 for red li
Bogdan [553]

Answer:

Explanation:

Using Snell's law

n₁ sinθ₁ = n₂ sinθ₂

for 420 nm wavelength

where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660

1.00 × sin 30° = 1.660 sinθ₂

sinθ₂ = 0.3012

θ₂ = sin⁻¹ 0.3012 = 17.53°

for 690 nm wavelength

n₁ sinθ₁ = n₂ sinθ₂

sinθ₂ = 0.5 / 1.630

θ₂ = sin⁻¹ 0.3067 = 17.86°

the angle between the two beam = 17.863° - 17.53° = 0.333°

7 0
3 years ago
Suppose your car accelerates from rest to 9 m/s in 2 s. Assume that the acceleration is constant in this time interval. A. What
Stolb23 [73]

Answer :

(a) The acceleration of the car is, 4.5m/s^2

(b) The distance covered by the car is, 9 m

Explanation :  

By the 1st equation of motion,

v=u+at ...........(1)

where,

v = final velocity = 9 m/s

u = initial velocity  = 0 m/s

t = time = 2 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

9m/s=0m/s+a\times (2s)

a=4.5m/s^2

The acceleration of the car is, 4.5m/s^2

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2 ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity  = 0 m/s

t = time = 2 s

a = acceleration  of the car = 4.5m/s^2

Now put all the given values in the above equation 2, we get:

s=(0m/s)\times (2s)+\frac{1}{2}\times (4.5m/s^2)\times (2s)^2

By solving the term, we get:

s=9m

The distance covered by the car is, 9 m

3 0
3 years ago
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