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vovikov84 [41]
3 years ago
6

Fill in the blank below: In a _______________ digestive system, digestion takes place outside of the cells in a series of tubes.

Food enters one opening and food remnants exit out of a different opening. Examples of organisms with this type of digestive system include you, dogs, horses, spiders and earthworms. A) Intracellular B) Sponge C) Incomplete D) Complete
Physics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer : Option D) Complete.

Explanation : In a complete digestive system, digestion takes place outside of the cells in a series of tubes. Food enters through one opening and food remnants exit out of a different opening. It has examples of humans, dogs, horses, spiders and earthworms. This system is complete because it does not occurs inside a cell nor it occurs in sponge kind-off organs and it is also not incomplete digestion as the waste products are removed from the other opening.

Therefore, the correct answer is option D) complete.

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Two devices with capacitances of 25 μf and 5.0 μf are each charged with separate 120 v power supplies. calculate the total energ
mash [69]
The energy stored in a capacitor is given by
U= \frac{1}{2} CV^2
where C is the value of the capacitance while V is the voltage difference applied to the capacitor.

Let's calculate the energy of the first capacitor:
U_1 =  \frac{1}{2} (25\cdot 10^{-6}F)(120 V)=1.5 \cdot 10^{-3}J

And now the energy of the second capacitor:
U_2 =  \frac{1}{2} (5 \cdot 10^{-6}F)(120 V)=3 \cdot 10^{-4}J

So, the total energy stored in the two capacitors is
U=U_1 +U_2 = 1.8 \cdot 10^{-3}J
3 0
3 years ago
Read 2 more answers
A merry-go-round with a a radius of R = 1.99 m and moment of inertia I = 194 kg-m2 is spinning with an initial angular speed of
Aleksandr [31]

Answer:

Part 1)

L_1 = 185.2 kg m^2/s^2

Part 2)

L_2 = 663.07 kg m^2/s^2

Part 3)

L = 663.07 kg m^2/s^2

Part 4)

\omega = 1.83 rad/s

Part 5)

F_c = 453.6 N

Explanation:

Part a)

Initial angular momentum of the merry go round is given as

L_1 = I \omega

here we know that

I = 194 kg m^2

\omega = 1.47 rad/s^2

now we have

L_1 = 194 \times 1.47

L_1 = 185.2 kg m^2/s^2

Part b)

Angular momentum of the person is given as

L = mvR

so we have

m = 68 kg

v = 4.9 m/s

R = 1.99 m

so we have

L_2 = (68)(4.9)(1.99)

L_2 = 663.07 kg m^2/s^2

Part 3)

Angular momentum of the person is always constant with respect to the axis of disc

so it is given as

L = 663.07 kg m^2/s^2

Part 4)

By angular momentum conservation of the system we will have

L_1 + L_2 = (I_1 + I_2)\omega

185.2 + 663.07 = (194 + 68(1.99^2))\omega

848.27 = 463.28 \omega

\omega = 1.83 rad/s

Part 5)

Force required to hold the person is centripetal force which act towards the center

so we will have

F_c = m\omega^2 R

F_c = 68(1.83^2)(1.99)

F_c = 453.6 N

3 0
3 years ago
A lens with f= 20.0 cm creates a
harina [27]

Answer:

h ’= 12,768 cm

Explanation:

For this exercise let's use the constructor equation

         1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

the magnification equation is

          m = h '/ h = -q / p

let's find the distance to the object

         1 / p = 1 / f- 1 / q

         1 / p = 1/20 - 1 / (- 37.5)

         1 / p = 0.076666

          p = 13.04 cm

now let's use the magnification equation

         h ’= - q / p h

let's calculate

         h ’= - (-37.5) / 13.04 4.44

         h ’= 12,768 cm

5 0
3 years ago
A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the slit widt
maw [93]

Answer:

shrinks with all the fringes getting narrower

Explanation:

As the light passes through the slit, the diffraction pattern shrinks, as the waves have more opening to penetrate, and the fringes becomes more narrow as a result of that, The opposite happens as the conditions are reversed.

8 0
4 years ago
A 2000kg car travelling east at 24/ms enters an icy intersection and collides with a 3600kg truck travelling south at 10 m/s. If
den301095 [7]
Resultant momentum is 60,000kgm/s 


60,000 = mass of cart and truck x velocity of car and truck
60,000= 5600 x V
V= 10.71428571 m/s
4 0
4 years ago
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