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3241004551 [841]
3 years ago
14

Water molecules on aluminum foil is an example of ____. a density b. freezing c. cohesion d. adhesion

Chemistry
1 answer:
hodyreva [135]3 years ago
3 0
D. adhesion because it is the intermolecular force attraction between different compounds.
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V=5, M=10 What is the density?
ch4aika [34]

Answer:

the answer to this question is  2 kilogram/cubic meter

Explanation:

4 0
3 years ago
What must occur before clouds can form?
fomenos
Evaporation must happen before they can form, because clouds are condensing, which means that they first have to evaporate, then they will condense, and form clouds.
5 0
3 years ago
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A solution is prepared by adding 0.10 mol of iron(III) nitrate, Fe(NO3)3, to 1.00 L of water. Which statement about the solution
MrMuchimi

Answer:

Option b is correct.

Explanation:

When Fe(NO_3)_3 is dissolved in water, Fe(OH)_2 and HNO_3 are formed.

Fe(NO_3)_3\; + 3H_2O \leftrightharpoons Fe(OH)_2\; + HNO_3

As Fe(OH)_2 is an weak base and HNO_3 is a strong acid, the resulting solution will be acidic in nature.

if K_b value is known, then pH of the solution can also be determined which will support prediction.

However, acidic and basic nature of the solution can be predicted without K_b value also.

So, among the given option, (b) is correct.

6 0
3 years ago
Calculate the volumetric size of a water molecule in water vapor at normal conditions, assuming 1 mole of the vapor occupies 22.
Vedmedyk [2.9K]

Let volumetric size of a water molecule = v

Since, 1 mole of water consists of 6.023\times 10^{23} molecules of water.

Thus, total volume of 1 mole of water = volumetric size \times 6.023\times 10^{23}

Substitute the value of total volume of 1 mole of water i.e. 22.4 L in above formula.

22.4 L = v\times 6.023\times 10^{23}

v= \frac{22.4 L}{6.023\times 10^{23}}

Convert the unit litre to angstrom

v=\frac{22.4 L}{6.023\times 10^{23}}\times \frac{1dm^{3}}{1L}\times \frac{(10^{9})^{3}(A^{o})^{3}}{1 dm^{3}}

= 3.7\times 10^{-23}\times 10^{27} (A^{o})^{3}

= 3.7 \times 10^{4}(A^{o})^{3}

Therefore, the volumetric size of the water molecule is 3.7 \times 10^{4}(A^{o})^{3}


8 0
3 years ago
If one starts with pure NO2(g) at a pressure of 0.500 atm, the total pressure inside the reaction vessel when 2 NO2(g) ⇌ 2 NO(g)
Anni [7]

Answer:

The equilibrium partial pressure of NO2 is 0.152 atm

Explanation:

Step 1: Data given

Initial pressure of NO2 = 0.500 Atm

Total pressure inside the vessel at equilibrium = 0.674 atm

Step 2: The balanced equation

2 NO2(g) ⇌ 2 NO(g) + O2(g)

Step 3: The initial pressures

pNO2 = 0.500 atm

pNO = 0 atm

pO2 = 0 atm

Step 4: The pressure at the equilibrium

pNO2 = 0.500 - 2x

pNO = 2x

pO2 = x

Total pressure = 0.674 = (0.500 - 2x) + 2x + x

0.674 = 0.500 + x

x = 0.174

pNO2 = 0.500 - 2*0.174 = 0.152 atm

pNO = 2x = 0.348 atm

pO2 = x = 0.176 atm

The equilibrium partial pressure of NO2 is 0.152 atm

4 0
3 years ago
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