Answer:
Weight
a) weight's vertical component = Normal upward force
b) weight's horizontal component = Friction force = (mass of ball)(acceleration)
These forces depend upon the track,
1) inclined or horizontal
2) steepness.
Explanation
The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.
weight's horizontal component = Friction force = (mass of ball)(acceleration)
The other component pushes the ball into the ramp, and the ramp pushes back.
If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. Hope this helps. Can u give me brainliest
Explanation:
d = distance = 0.76 m <span>
<span>a = acceleration due to gravity = 9.81 m/s^2</span>
u = initial velocity = 0 (as the ball rolls off the table the
vertical velocity = 0
t = time = missing so we need to solve it
So we use the equation d = ut + 1/2 at², and ever since u is
zero, ut is zero and the equation becomes to d = 1/2 at² and this reorders to t
= sqrt (2d/a) = 0.39 seconds.
Since there are no forces performing in the horizontal
direction, this means that there is no acceleration in the horizontal direction
and consequently the horizontal velocity is persistent. </span>
Velocity = distance/
time.
Horizontal velocity is
therefore horizontal distance/time = 0.61 m/0.39s = 1.56 m/s.
<span> </span>
Answer:
The number of bright fringes per unit width on the screen is,
Explanation:
If d is the separation between slits, D is the distance between the slit and the screen and
is the wavelength of the light. Let x is the number of bright fringes per unit width on the screen is given by :
![x=\dfrac{n\lambda D}{d}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7Bn%5Clambda%20D%7D%7Bd%7D)
is the wavelength
n is the order
If n = 1,
![x=\dfrac{\lambda D}{d}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D)
So, the the number of bright fringes per unit width on the screen is
. Hence, the correct option is (B).