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Naddik [55]
3 years ago
12

A book is pushed and released and it slides across a table for a short distance. The book quickly comes to a stop. The book orig

inally has kinetic enrgy. To what form of energy is the kinetic energy transformed? A) The kinetic energy is transformed into heat. B) The kinetic energy is transformed into chemical energy. C) The kinetic energy is transformed into potential energy. D) The kinetic energy is transformed into electrical energy..
Physics
2 answers:
Burka [1]3 years ago
4 0

a the kinetic energy is transformed into heat

Naya [18.7K]3 years ago
3 0

Answer:

The kinetic energy is transformed into heat.

Explanation:

Energy cannot be created or destroyed it can only change forms. Friction stops the book and creates heat.

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Consider a Cassegrain-focus, reflecting telescope. Images recorded at Cassegrain-focus will be:
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B. Flipped compared to what is in the sky
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A box is against a wall. A person pushes on the box, but the box does not move. Is this
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it is a force

Explanation:

a force is a push or a pull

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An Olympic high jumper, with a mass of 82 kg, has a
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I don't really know

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3 years ago
Two tugboats are moving a barge. Tugboat A pushes on the barge with a force of 3000n. Tugboat B pulls with a force of 5000 Newto
kenny6666 [7]

The net force on the barge is 8000 N

Explanation:

In order to find the net force on the badge, we have to use the rules of vector addition, since force is a vector quantity.

In this problem, we have two forces:

  • The force of tugboat A, F_A = 3000 N, acting in a certain direction
  • The force of tugboat B, F_B = 5000 N, also acting in the same direction

Since the two forces act in the same direction, this means that we can simply add their magnitudes to find the net combined force on the barge. Therefore, we get

F=F_A+F_B = 3000 + 5000 = 8000 N

and the direction is the same as the direction of the two forces.

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5 0
4 years ago
In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
Leya [2.2K]

Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

mass of plate, m=10.7\ kg

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

I_{cm}=\frac{1}{12} \times m(L^2+B^2)

where:

L= length of the plate

B= breadth of the plate

I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

I_{cm}=0.6591\ kg.m^2

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}

s=0.4299\ m

Now using parallel axis theorem:

I=I_{cm}+m.s^2

I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

6 0
3 years ago
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