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Setler79 [48]
3 years ago
7

500 ml of four different liquids are heated to 50oC. According to the specific heat data, which liquid will cool to 35oC in the

shortest amount of time?
Physics
2 answers:
sergiy2304 [10]3 years ago
7 0
That would be Gasoline.
GuDViN [60]3 years ago
3 0

Answer:C) gasoline

Explanation:

Specific heat is the measure of the heat energy required to increase or decrease the temperature of a substance by a certain temperature interval. Gasoline has the lowest specific heat; that means it takes less energy to lower or raise the temperature of gasoline compared to the other three liquids.

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An object dropped on Planet P falls 144 m in 6 seconds. What is the gravitational acceleration of Planet P ? Gravitational accel
Tju [1.3M]

Answer:

The gravitational acceleration of the planet is, g = 8 m/s²

Explanation:

Given data,

The distance the object falls, s = 144 m

The time taken by the object is, t = 6 s

Using the III equations of motion

                  S = ut + ½ gt²

∴                 g = 2S/t²

Substituting the given values,

                   g = 2 x 144 /6²

                      = 8 m/s²

Hence, the gravitational acceleration of the planet is, g = 8 m/s²

7 0
4 years ago
Pls help i’ll give brainliest if you give a correct answer!!
enot [183]

Answer:

the second one

Explanation:

4 0
3 years ago
Please view image attached!
Marat540 [252]

Answer:

you would expect a change in the graph

Explanation:

8 0
3 years ago
You're in a car that gets 37 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and
Sergeu [11.5K]

Answer:

Required diameter of hose pipe = 0.2864 mm

Solution:

From the continuity eqn, the fluid flow rate is given by:

Av = \frac{V}{t}

where

A = cross-sectional area = \pi r^{2}

r = hose pipe radius

v = velocity of gas

Also, v = \frac{displacement, d}{time, t}

Using:

1 gallon = 3.854 l

1 mile = 1609.34 m

1 m^{3} = 1000 l

Therefore,

A\frac{d}{t} = \frac{V}{t}

\pi r^{2} = \frac{V}{d}

\pi r^{2} = \frac{(1 gal).(\frac{3.7854 l}{gal}).(\frac{10^{- 3} m^{3}}{l})}{37 miles(\frac{1609.34 m}{miles})}

6.357\times 10^{- 8} = \pi r^{2}

r^{2} = 2.024\times 10^{- 8}

r = 1.423\times 10^{- 4} m = 0.1423 mm

The diameter of the hose pipe = 2r = 2\times 1.423\times 10^{- 4}

The diameter of the hose pipe = 2.846\times 10^{- 4} m = 0.2846 mm

4 0
4 years ago
Stream systems that have a low sediment load and low velocity and flow over unconsolidated sediments form _____________ stream c
Vladimir [108]

Answer:

Meandering

Explanation:

A meander is known as the continuous flow of regular curves which are sinuous, loops, turns, bends or winding in the channel of river

Production of a meander by a river or stream  as it erodes the sediments comprising on an exterior, a concave bank and deposits it and other sediment on the downstream on an interior, convex bank which is like a point bar.

Rivers or streams  with a one channel and sinuosities of 1.6 or more are defined as meandering rivers or streams.

4 0
3 years ago
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