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Aloiza [94]
3 years ago
15

How to solve number 13

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

a) Each year the price increases by 3%, so if burger initially has price p=\$3.99, then next year its price will be 1.03p\approx\$4.11. After another year, this price will increase by 3%, so that the burger would cost 1.03^2\approx\$4.23.

b) If the same pattern continues, then 10 years later we should expect the price to be 1.03^{10}p\approx\$5.36.

c and d) The pattern appears to be that the price p of the burger after t years, starting at a price p_0, is

p(t)=1.03^tp_0

which forms a geometric sequence that diverges. This necessarily means that the price would eventually exceed $20, and we find that that time comes about

\$20=1.03^t(\$3.99)\implies t\approx54.5

years later.

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Carlos and Maria drove a total of 233 miles in 4.4 hours. Carlos drove the first part of the trip and averaged 55 miles per hour
11Alexandr11 [23.1K]
So basically
D=RT
distance=rate times time

D=233
carlos speed=55
maria speed=50
total time=4.4 hours

so therefor we have to represent
carlos time
maria time
carlos distance
maria dstance

let's say that
remember that whatever carlost drove is 233 minus maria (time and distance)
and since we are solving for maria time and distnace, solve in terms of them
maria time=t
maria distance=d
carlos time=4.4-t
carlos distance=233-d

remember total D=RT
find their seperate equations
carlos
233-d=55(4.4-t)

maria
d=50(t)
use them to solve

233-d=55(4.4-t)
subsitute 50(t) for d
233-50t=55(4.4-t)
add 50t to both sides
233=55(4.4-t)+50t
distribute using distributiver protperty (a(b+c)=ab+ac)
55(4.4-t)=242-55t
233=242-55t+50t
add like terms
233=242-5t
add 5t to both sides
233+5t=242
subtract 233 from both sides
5t=9
divdie both sides by 5
t=1.8
maria drove 1.8 hours

the answer is A
8 0
3 years ago
A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib
fenix001 [56]

Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0
3 years ago
Briainliest Simplify 15√90/√125<br> options<br> 9√2<br> 18√5<br> 18√2/5<br> 27√2/5
nekit [7.7K]

Answer:

9√2

Step-by-step explanation:

simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Exact form:9√2

Decimal form: 12.72792206

3 0
3 years ago
Solve the system of linear equations below 2x-y=0 3x-2y=-3
Lynna [10]
2x - y = 0
2x = y

3x - 2(2x) = -3
3x - 4x = -3
-x = -3
x = 3

2(3) = y
6 = y
3 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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