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Serggg [28]
4 years ago
7

During your summer internship for an aerospace company, you are asked to design a small research rocket. the rocket is to be lau

nched from rest from the earth's surface and is to reach a maximum height of 940 m above the earth's surface. the rocket's engines give the rocket an upward acceleration of 16.0 m/s2 during the time t that they fire. after the engines shut off, the rocket is in free fall. ignore air resistance. part a what must be the value of t in order for the rocket to reach the required altitude?
Physics
1 answer:
pickupchik [31]4 years ago
8 0
X=.5a(t^2), x=940, a=16, t=?. ((940x2)/16)^.5=t=10.84s. 
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The Mass of a Body
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Answer:

Acceleration does not affect mass. Acceleration only affects weight.

Explanation:

Your mass is the same on Earth compared to on the moon, but your weight is going to be different because the acceleration due to gravity is going to be different.

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3 years ago
The Earth rotates once every day. What is the velocity of a person on its surface, if the radius of Earth is 6 million meters
LekaFEV [45]

Answer:

v = ω R

number of seconds in 24 hrs = 24 * 3600 = 86400 s / da = T (period)

f = 1 / T

ω  = 2 Π f = 2 Π / T = 2 Π / 86400

v = 2 Π / 8.64E4 * 6.0E6 = 436 m / s

Check:

S = 2 Π * 6.0E6 = 3.77E7 m/da

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2 years ago
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8 0
3 years ago
Objects falling through air experience a type Of friction called ____
DaniilM [7]

Answer: That's air resistance.

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6 0
4 years ago
Read 2 more answers
uppose that 3 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 45 cm. (a) How much work i
Lesechka [4]

Answer:

(a) The work done is 0.05 J

(b) The  force will stretch the spring by 3.8 cm

Explanation:

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work done in stretching the spring from 30 cm to 45 cm, W = 3 J

extension of the spring, x = 45 cm - 30 cm = 15 cm = 0.15 m

The work done is given by;

W = ¹/₂kx²

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k is the force constant of the spring

k = 2W / x²

k = (2 x 3) / (0.15)²

k = 266.67 N/m

(a) the extension of the spring, x = 37 cm - 35 cm = 2 cm = 0.02 m

work done is given by;

W = ¹/₂kx²

W = ¹/₂ (266.67)(0.02)²

W = 0.05 J

(b) force = 10 N

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F = kx

x = F / k

x = 10 / 266.67

x = 0.0375 m

x = 3.75 cm = 3.8 cm

Thus a force of 10 N will stretch the spring by 3.8 cm

7 0
3 years ago
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