**The stone lands 133 m far from the bottom of the cliff**

**Explanation:**

The motion of the stone in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by considering the vertical motion: since it is a free fall motion, we can use the suvat equation

where

s = 85 m is the vertical displacement, the height of the cliff (we chose downward as positive direction)

u = 0 is the initial vertical velocity of the stone

t is the time the stone takes to reach the ground

is the acceleration of gravity

Solving for t, we find the time:

Now we can consider the horizontal motion, which is a uniform motion at constant speed. The horizontal distance travelled is given by
:

where we know:

is the horizontal velocity, which is constant

t = 4.16 s is the time of flight

Solving for d, we find:

So, the stone lands 133 m far from the base of the cliff.

Learn more about** projectile motion** here:

brainly.com/question/8751410

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