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Anna007 [38]
3 years ago
13

The product of a number and 3 is the same as the sum of that number and six

Chemistry
2 answers:
attashe74 [19]3 years ago
8 0
The number is 3
because if the number was x it would be 3x=x+6
And x=3
Ann [662]3 years ago
8 0

Answer:

x=3

Explanation:

Hello,

Such equality in this case is:

3x=6+x

Solving for x one obtains:

3x-x=6\\2x=6\\x=\frac{6}{2}\\ x=3

Best regards.

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Find the density of a material, given that a 5.01 g sample occupies 3.46 mL
Alex73 [517]

Answer:

The answer is

<h2>1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of material = 5.01 g

volume = 3.46 mL

The density of the material is

density =  \frac{5.01}{3.46}  \\  = 1.44797687...

We have the final answer as

<h3>1.45 g/mL</h3>

Hope this helps you

3 0
3 years ago
How are amounts of hydrogen and oxygen gas made from the electrolytic decomposition of water related to the chemical formula of
Len [333]
Very simply, you get twice as much Hydrogen as Oxygen, because the chemical formula is H2O, meaning two hydrogen atoms bonded to one oxygen atom.
4 0
3 years ago
Were are electrons located
lukranit [14]
Electrons are found in the cloud that's surrounded the nucleus of an atom 
8 0
3 years ago
Read 2 more answers
How many pi bonds are in the oxalate ion (C2O42-)?
suter [353]

Answer:there are 13

Explanation:

4 0
2 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST
kirill115 [55]

The amount of heat required to convert H₂O to steam is :  382.62 kJ

<u>Given data :</u>

Mass of liquid water  ( m ) = 150 g

Temperature of liquid water = 43.5°C

Temperature of steam = 130°C

<h3 /><h3>Determine the amount of heat required </h3>

The amount of heat required = ∑ q1 + q2 + q3 ----- ( 1 )

where ;

q1 = heat required to change Temperature of water from 43.5°C to 100°C .  q2 = heat required to change liquid water at 100°C to steam at 100°C

q3 = heat required to change temperature of steam at 100°C to 130°C

  • For q1

M* S_{water}*ΔT

= 150 * 4.18 * ( 100 - 43.5 )

= 35425.5 J

  • For q2

moles * ΔHvap

= (150 / 18 )* 40.67 * 1000

=  338916.67 J

  • For q3

M * S_{steam} * ΔT

= 150 * 1.84 * ( 130 -100 )

= 8280 J

Back to equation ( 1 )

Amount of heat required = 35425.5  + 338916.67 + 8280 = 382622.17 J

                                                                                               ≈ 382.62 kJ

Hence we can conclude that The amount of heat required to convert H₂O to steam is :  382.62 kJ.

Learn more about Specific heat of water : brainly.com/question/16559442

6 0
2 years ago
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