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Bond [772]
4 years ago
7

Why is the charge on a charged sphere distributed uniformly over its surface

Physics
2 answers:
icang [17]4 years ago
6 0

Answer:

As we know that all conductors are equipotential so we can say that all points lie on the surface of conductors will be at same potential.

So here we can say that

V = \frac{kQ}{R}

V = \frac{Q}{4\pi \epsilon_0 R}

now we will multiply numerator and denominator by radius R

so here we will have

V = \frac{QR}{4\pi R^2 \epsilon_0}

now we know that

\sigma = \frac{Q}{4\pi R^2}

so we have

V = \frac{\sigma R}{\epsilon_0}

since potential is constant so here charge density and radius product will remain constant always

so here on spherical conductor the charge density will remain same at all points

s2008m [1.1K]4 years ago
4 0
Similar charges repel each other and thus are spread throughout the surface if the surface is conductive.
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