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3 years ago

Compare these two waves.

Physics

1 answer:

Anastaziya [24]3 years ago

5 0

Answer:

id 272 966 3863

Pas 161005

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4. What determines which goods a country should produce and export?

tangare [24]

Answer:

net exporter

Explanation:

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2 years ago

In which state of matter are water molecules measured as having a comparatively high temperature?

AnnZ [28]

Liquid water because if it said very high then it would be water vapor but it didn’t say that so the answer is B liquid water

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3 years ago

PLEASE HELP ASAP!! What are 3 types of forces acting on your marshmallow (or other flying object) when it impacts it’s target? C

Alekssandra [29.7K]

•Every action has an equal and opposite reaction (the object is putting force on the target, and the target is putting an equal amount of force back)
•Am object in motion (the object) will stay in motion unless an outside force acts upon it (the Target)

And as for the third one I really don’t know, those seem to be the only two, I’m sorry. I did what a could, Hope it kinda helps :)

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3 years ago

20. A cannon shoots a ball at 38 m/s at an angle of 30°. Ignore the original height of the cannon and assume level ground.

sergij07 [2.7K]

Answer:
a.3.87s
b.127.36m
c.18.4m

Step by step explanation:
Refer to the diagram

5 0

3 years ago

When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai

geniusboy [140]

Answer:

The total frictional force is 358.0 newtons

Explanation:

Power is the amount of average work (W) an object does on a period of time (Δt):

$P=\frac{W}{\Delta t}$

Remember average work is average force (F) times displacement (Δs):

$P=\frac{F \Delta s}{\Delta t}$

but displacement over time is average speed $v=\frac{\Delta s}{\Delta t}$ , then:

$P=Fv$ (1)

That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

$F=\frac{P}{v}$

Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308 $\frac{m}{h}$ = $62.5 \frac{m}{s}$ , then:

$F=\frac{22380}{62.5}=358.0 N$

6 0

3 years ago

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